Recent content by djkinney

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    How Much Sand Equals the Surface Area of a Cube?

    Homework Statement Grains of fine California beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide, which has a density of 2.6 × 103 kg/m3. What mass of sand grains would have a total surface area (the total area of all the individual spheres)...
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    Laying on the beach while sunseting question

    I have no preference about length of finding a solution as long as it's the correct one. Thank you so much once again!
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    Laying on the beach while sunseting question

    Wow, I would've never done that. Even my calculus professor didn't tell me that. Thank you so much guys for your help!
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    Laying on the beach while sunseting question

    Okay, so when I solve for the angle I get .0454° Then take the cos of the angle in which I get ≈ .9897 Then I set that equal to R/(R+h) h=1.58 → .9897=R/(R+1.58) Solve for R by multiplying .9897(R+1.58)=R Then get like terms of one side 1.59=R-R(.9897) A R can be taken out 1.59=R(1-.9897)...
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    Laying on the beach while sunseting question

    Okay, so that means that 1.26E^-4*360°=.04536° for the angle? Then I would still be getting my final answer as 1.5E^3
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    Laying on the beach while sunseting question

    Hey, Well I'm not quite sure as to how to get the angle. I tried two different ways so far: First, I tried: 10.9s/86400s=1.26e-4°. The second was me trying something crazy and doesn't make any sense: 10.9s*(1min/60s)*(1hr/60min)*(360/24hr)=.0454°
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    Laying on the beach while sunseting question

    Homework Statement Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a stopwatch just as the top of the sun disappears. You then stand, elevating your eyes by a height H = 1.58 m, and stop the watch when the top of the...
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