Recent content by doey

∫1/5+4sin(deta) dθ =∫(dz/iz)/[5+4(z/2i-1/2iz)] = ∫(dz)/[5iz+4(iz^2/2i-iz/2iz)] = ∫(dz)/[5iz+(4iz^2)/(2i)-4iz/2iz)] =∫(dz)/[5iz+2z^2-2] then i nid solve 5iz+2z^2-2 to get my pole,am i wrong? then i will...

Homework Statement it ask me to integral from 0 to 2pi for 1/[5+4sin(deta)]Homework Equations i knoe i nid to find out the pole bu convert sin(deta) into exponential fomat The Attempt at a Solution after i solve it until 2z^2+5iz-2 i stucked,can i juz use [-b+-squarot[b^2-4ac]]/2a formula to...

ok,i try to solve for integrate z dz= x+iy(dx+idy) and get dy dx from y=2x.and i get the answer for integrate z dz, how about the answer for integrate complex conjugate of z? since complex conjugate of z is not analytical .can i do it in the same way oso?

Homework Statement evaluate contour integral ∫ Z dz from 0 to 1+21 in the curve of y=2x

[b]1. Homework Statement [/b from -∞ to ∞ of ∫1/(x^4+1) dx Homework Equations how can i actually find out the pole of this function The Attempt at a Solution i try to determine the pole and x^4=-1,for this i have obtain the root which is (-1)^1/4,but i dun noe how to find out the...

Homework Statement given 5z^4+z^3+2 Homework Equations the question asking me to find the contour integral of thi function in the C circle of |z|=1. then how about if the Contour is a square with point [0,0][1,0][1,i][0,i] ? The Attempt at a Solution i have no idea abt how to do...

(1) \int_0^{\pi/2} \cos^2 (\frac{\pi}{2} \cos\theta) d\theta ,i am asking this pls let me know the steps it takes

i facing a maths problem in integrating ∫ cos^2(∏/2cosθ) with limit from 0 to ∏/2,i was panic and struggled a long period of time in solving this,anyone can help me? pls give me the answer in detail tq !

i guess i know what you means,but only a way there i not really sure,is there we can just put the front of e^mx with an function ? by making it into u(x)e^mx.

ay'' + by' + cy = 0 1) for 2 distinct roots,the solution should be y = Ae^m1x + Be^m2x 2) for Real and equal roots should be y = e^mx(A + Bx) that is it. So if same roots as the 2nd one,one solution is y1(x)=Ae^mx, what about the second solution? there is a second solution given...

ya,i was thinking this a whole night time== here i come out an answer: just like a person stand still on the floor,he has weight because the floor acting an upward force which respond toward the gravity. F=w(W is the upward force ,we call it Weight) when you having another force that pulling...

is it means we are just weightless because of we cannot weight it in scale?I was confounded.it just stated when an object is in free fall,it is pulling by gravity ,it cannot be weightless.then how come it become weightless indeed as you told in number 2(above) as i know ,it might be apparently...

sry for all that my posted consisting unclear and make all confuse.I knew I was mistaken the concept ==

we are in weightless condition because there are no resultant force between Earth and me,at this instant, Earth and me are in the opposite direction moving toward each other,will Earth oso can consider weightless? when i free falling p/s : beg pardon at 1st typing massless ,typing error ==

degree in engineering is enough for getting into jobs with high pay.less people will consider in taking Mc i think.It really depends on working experience and proficiency