What are the complex poles of the function 1/(x^4+1)?

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SUMMARY

The function f(x) = 1/(x^4 + 1) has no real poles, as the equation x^4 + 1 = 0 does not yield real solutions. However, it possesses four complex poles, which can be determined by solving for the roots of the equation in polar form. The roots can be expressed as r e^{i θ}, where r is the magnitude and θ represents the angle in the complex plane. Understanding these complex poles is essential for evaluating the integral from -∞ to ∞ of f(x).

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1. Homework Statement [/b
from -∞ to ∞ of ∫1/(x^4+1) dx

Homework Equations


how can i actually find out the pole of this function


The Attempt at a Solution


i try to determine the pole and x^4=-1,for this i have obtain the root which is (-1)^1/4,but i dun noe how to find out the remaining roots and it really make me confuse for this ==
 
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Since x4+1 = 0 has no real-valued solutions, your function f(x) = 1/(x4+1) has no poles. You'll need a different approach for this integral.
 
Michael Redei said:
Since x4+1 = 0 has no real-valued solutions, your function f(x) = 1/(x4+1) has no poles. You'll need a different approach for this integral.

There are complex poles. There are four of them. Write the root in polar form [itex]r e^{i \theta}[/itex] and try and figure out what the possibilities are for r and [itex]\theta[/itex].
 

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