Recent content by donjt81

Hi guys I was solving a problem and I am stuck at solving this equation. (sec x)^2 (tan x)^2 = 2 since we know that (sec x)^2 = 1 + (tan x)^2 [1 + (tan x)^2][(tan x)^2] = 2 (tan x)^2 + (tan x)^4 - 2 = 0 now what do i do... thanks in advance.

thanks guys i completely missed that. you are right it should be -4 to 4... other than that does everything else look ok.

So here is the question find the volume of the solid generated by revolving the region bounded by the curve y = sqrt(16 - x^2) and the line y = 0 about the x axis. this is how I solved it \int_{0}^{4} \Pi (16 - y^{2}) \; dy \Pi \int_{0}^{4} (16 - y^{2}) \; dy pi(16*y - y^3/3)...

so let me see if I understand this correctly. \int_{-1}^{3} (2y-y^{2}) - (-3) \; dy is that correct?

Hi guys, I need some help on this. It is in the integral section so I am assuming you use integrals for this. Can someone point me in the right direction. Find the total area enclosed by the line x = -3 and the curve x = 2y - y^2

ohhh ok so... y' = 3x^2/5 + C 1 = 3(-2)^2/5 + C C = -1.4 y = x^3/5 + Cx + D 3 = -2^3/5 - 1.4 * -2 + D D = 1.8 So the eqn of the graph is y = x^3/5 - 1.4x + 1.8 is that correct?

problem: find the anti derivative of x^5 + tan(2x)sec(2x)dx how do you find the anti derivative of the second half of that problem tan(2x)sec(2x)

ok so y' = 3x^2/5 + C y = x^3/5 + Cx + D and also we have the point (-2,3) and slope 1 if we substitute the values for x and y here we get 3 = -8/5 -2C + D ?? how do we get the values of C & D... I'm stuck...

Hi I have this problem where I have to find the equation of the graph using derivatives or anti-derivatives... I'm not sure... I really need some help on this... Find the equation for the graph that passes through the point (-2,3) with the slope 1 given that d^2y/dx^2 = 6x/5 can someone...

ohhhh! duhhh! I shouldve known... thanks

what is k?

I am doing this problem and I am getting stuck at solving the equation problem: Use the second derivative test to determine the concavity of the following function. y = x(cosx) at x = pi/3 solution: y' = -xsinx + cosx y'' = -xcosx - 2sinx = 0 and then i did -xcosx = 2sinx ( i don't...

problem: Use the graphing strategy to sketch the graph of y=(4x)/(x^2+1). check the intervals where it is concave up and where it is concave down. Then graph it. please use sign charts. to find this we have to first find y''. so I used the quotient rule twice to get this y'' = (8x^5 - 16x^3...

ok so i have this problem where i am asked to find the asymptotes. It is kinda throwing me off because it is in the middle of the differentiation section. so here is the problem problem: use the graphing strategy to sketch the graph of y=(4x)/(x^2+1). check for domain values, intercepts...

Thanks xman... yes it looks correct... can anyone else look at it and confirm it? I want to make sure i do the homework right.