The discussion revolves around finding the antiderivative of the expression x^5 + tan(2x)sec(2x)dx, with a particular focus on the second term, tan(2x)sec(2x).
The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the use of u-substitution, and there is an acknowledgment of the derivative relationship between secant and tangent functions. Participants reflect on their thought processes and the potential for learning from their approaches.
There is an indication that participants are working within the constraints of a homework assignment, which may influence their approaches and reasoning. The discussion also highlights the importance of careful consideration of the problem before proceeding with manipulations.
donjt81 said:problem: find the anti derivative of x^5 + tan(2x)sec(2x)dx
how do you find the anti derivative of the second half of that problem tan(2x)sec(2x)
prace said:yeah, you are going to have to use u-substitution twice. I don't know if I am correct or not, but I changed everything to sin and cos before anything and manipulated it that way. I then let u = cosx and du = -sinx. For the second u-substitution, I let v=u²-1 and (1/2)dv = udu. I hope that helps and does not confuse you and more.