Recent content by dopey9

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    Proof of Square Root Limit Theorem for Continuous Functions

    square root limit proof R is the real nmbers so let A be in R let f: A -> R be such that f(x)>0 for all x in A c is in A Does anyone know the proof to or even get me started on this proof shown below [It's hard to write roots on the computer, so I will use the 1/2-th power instead.]...
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    Answer Modulus of Speed: Calculation w/fluid mech.

    Homework Statement i just want to know what the modulus of the speed (u) would if Homework Equations u = (-2/r)[SIZE="4"]e[SIZE="1"]r + (2/r)[SIZE="4"]e[SIZE="1"]theta The thing is i get confused with the [SIZE="4"]e[SIZE="1"]r and [SIZE="4"]e[SIZE="1"]theta ..do these just mean the...
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    Proving feasibility of convex linear combination in LP problem

    Let x[SIZE="1"]1, . . . , x[SIZE="1"]k be feasible solutions of the linear programming problem: Maximize z = (c^t)*x subject to Ax < = b and x >= 0, so for i= 1, . . . , k, Ax[SIZE="1"]i <=b and x[SIZE="1"]i >=0, Let v be any convex linear combination of x[SIZE="1"]1, . . . ...
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    Solving Complex Potential Equation - Find Streamfunction, Potential

    streamline question i was wondering if my u is right, as my problem deals with two dimensional inviscid steady potential flow and there are are various ways to find u = u(r,theta)e[SIZE="1"]r + v(r,theta)e[SIZE="1"]theta u= (-2/r)*e[SIZE="1"]r +(2/r)*e[SIZE="1"]theta and if so i was...
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    Solving Complex Potential Equation - Find Streamfunction, Potential

    Thanks that makes sense..i got it in my notes but just don't when to apply it
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    Solving Complex Potential Equation - Find Streamfunction, Potential

    Homework Statement Iv been given the complex potential equation ..iv been trying to split it into real and imaginary parts so i can find the streamfunction and potential for it...however the ln is making it difficult Homework Equations The Attempt at a Solution iv tried...
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    Proving the Three-Component Formula for Fluid Mechanics Forces

    Can someone help me with this proof
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    Asymptotic Behaviour of Solution x(t) for dx/dt = x^4 +4(x^3) - 60(x^2)

    i have the ode dx/dt = x^4 +4(x^3) - 60(x^2) generally the solution s x(t) satisfy x(0) = x[0] and i found out that the attactor is -10 repellor is 6 and 0 is niether however i want to describe the asymptotic behaviour of the solution satisfying x(0) = 1/2 , which is were i...
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    Are the Limits of an Increasing Function the Same?

    A function f : A ->R is increasing if f(x) <= f(y) for every x, y in A such that x <= y. Suppose that f : [a, b] -> R is increasing and that a < c < b. i want to shat that : lim f(x) = sup{f(x) | a <= x < c} and x->c- limf(x) = inf{f(x) | c < x <= b}. x->c+ and whether these...
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    Forces with direction and magnitude

    Dont worry about it ...iv left it out..thankz for help...but if u do want the full question ...the first one i posted...and the last one i jus posted ...and that's all i was given..there was no diagram thankz anyway
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    Forces with direction and magnitude

    ... but this is what i have taken from a past paper...it says "the couple of the total force about the point with position vector i is zero" ...its confusing me too...thankz for the help tho
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    When Will Ships P & Q Be Closest to Each Other?

    can i just confirm that are these parts right that i answered before...because i wasnt too show whether a negitive sign is requied with the 10 coz of the direction?: "Iv found the co-ordinates of Q relative to P at t=0 ---->X=(10,10)km iv also found the velocity of Q relative to P----> V=...
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    When Will Ships P & Q Be Closest to Each Other?

    A ship P is traveling due East at 30 km/h and a Ship Q is traveling due South at 40 km/h. Both ships keep constant speed and course. At t=0 they are each 10 km from the point of intersection of their courses and moving towards the point. Iv found the co-ordinates of Q relative to P at...
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    Forces with direction and magnitude

    Forces/couple! particle of mass m kilograms is acted on by two forces F[1] and F[2] with magnitudes 3*sqr-root 5 Newtons and sqr-root 5 Newtons and directions parallel to the vectors i+2j and i-2j respectively. The particle is initially at a position given by the vector 2i+j i was told to...
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