When Will Ships P & Q Be Closest to Each Other?

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Homework Help Overview

The discussion revolves around the motion of two ships, P and Q, traveling at constant speeds in perpendicular directions. Ship P is moving east at 30 km/h, while Ship Q is moving south at 40 km/h. Both ships start 10 km from the intersection point of their paths. The original poster is attempting to determine the time at which the ships are closest to each other.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss finding the relative coordinates and velocities of the ships. There are suggestions to express the distance between the ships as a function of time and to minimize that function. Some participants question the correctness of the initial calculations regarding relative positions and velocities.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's calculations and suggesting methods to approach the problem. There are differing opinions on the necessity of calculus in solving the problem, and some participants are exploring various interpretations of the setup.

Contextual Notes

There is uncertainty regarding the signs of the coordinates due to directional considerations, and participants are clarifying the setup of the problem as they work through the details.

dopey9
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A ship P is traveling due East at 30 km/h and a Ship Q is traveling due South at 40 km/h.
Both ships keep constant speed and course. At t=0 they are each 10 km from the point of intersection of their courses and moving towards the point.

Iv found the co-ordinates of Q relative to P at t=0
---->X=(10,10)km

iv also found the velocity of Q relative to P----> V= V[Q] -V[P]
-----.V= (0,40) - V(30,0)
----- V= (-30,40)km/h

but I am struggling to find the time at which P and Q are closest to each other...is there anyone that can help? thankz
 
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Find an expression for the distance between the ships as a function of time and minimise that with respect to time.
 
dopey9 said:
Iv found the co-ordinates of Q relative to P at t=0
---->X=(10,10)km
OK.

iv also found the velocity of Q relative to P----> V= V[Q] -V[P]
-----.V= (0,40) - V(30,0)
----- V= (-30,40)km/h
V[Q] = (0, -40)



but I am struggling to find the time at which P and Q are closest to each other
The trajectory of Q with respect to P is just a straight line. Write the equation of that line and then find the point on that line closest to point P. (There are several ways to do that.)
 
can i just confirm that are these parts right that i answered before...because i wasnt too show whether a negitive sign is requied with the 10 coz of the direction?:
"Iv found the co-ordinates of Q relative to P at t=0
---->X=(10,10)km

iv also found the velocity of Q relative to P----> V= V[Q] -V[P]
-----.V= (0,40) - V(30,0)
----- V= (-30,40)km/h "
 
neutrino said:
Find an expression for the distance between the ships as a function of time and minimise that with respect to time.
Maybe I am misunderstanding your use of minimize, but there is no need for calculus here.

For the topic creator, you are pretty close and really just need to resolve your new vectors in a single linear equation. Then once you have your distance and velocity you know that a change in distance over a change in velocity is time.
 
dopey9 said:
"Iv found the co-ordinates of Q relative to P at t=0
---->X=(10,10)km
Right.

iv also found the velocity of Q relative to P----> V= V[Q] -V[P]
-----.V= (0,40) - V(30,0)
----- V= (-30,40)km/h "
Wrong. (As I pointed out earlier.)
 

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