Recent content by dragon18

I figured out that the answer is 1.898102N F=45F*m/(0.300m*sin(52.6°))

If θ=0, then the force would be 150N. θ isn't the angle between the force and displacement, but what am I looking for instead of 52.6°?

Starting from rest, an object is sliding down a frictionless inclined plane on the planet Org. Using the animation, determine the acceleration due to gravity ('g') on the planet. Use the protractor shown on the screen to measure the angle of inclination...

You are installing a new spark plug in your car, and the manual specifies that it be tightened to a torque that has a magnitude of 45.0 N*m. Using the data in the figure below (L = 0.300 m and ? = 52.6°), determine the magnitude F of the force that you must exert on the wrench. Relevant...

which number do I use though? It keeps telling me its wrong no matter what I put

so do I use the equation v=u+at?

On a spacecraft two engines fire for a time of 572 s. One gives the craft an acceleration in the x direction of ax = 5.15 m/s2, while the other produces an acceleration in the y direction of ay = 7.41 m/s2. At the end of the firing period, the craft has velocity components of vx = 3782 m/s and...

In the vertical direction I got 1.91 m/s^2 for acceleration. I think the horizontal acceleration in 5.44 m/s^2. I am sorry, I'm just very bad at following written directions

I got 13.15N for the horizontal and 53.50N as the vertical. I don't really know if those are correct and I don't understand what to do afterwards.

F1=56.8 N F2=39.2 N Weight of the block is 70.56, so the force the table is exerting upward on the block is 70.56 N. So the net force is 166.56N? I know that if I divide that by the mass, I will not get the correct answer. So what's next?

Two forces, F1 and F2, act on the m = 7.20 kg block shown in the figure below. The magnitudes of the forces are F1 = 56.8 N and F2 = 39.2 N. θ = 70.4°. What is the magnitude of the horizontal acceleration of the block? Relevant equations V0x=v0cosθ V0y=v0cosθ F=ma The attempt...

Three students converge on the last textbook in the store. All three grab it and begin to pull in the directions shown in the above figure. Student A exerts a force of 61.88 N, student B pulls with a force of 31.92 N, and student C pulls with a force of 104.20 N at an angle θ(theta)=80.8 degrees...