# Calculating Horizontal Acceleration on 7.20 kg Block w/F1 & F2

• dragon18
In summary: Given that there are no other horizontal forces, the block will accelerate horizontally through the table at 5.44 m/s^2.
dragon18
Two forces, F1 and F2, act on the m = 7.20 kg block shown in the figure below.

The magnitudes of the forces are F1 = 56.8 N and F2 = 39.2 N. θ = 70.4°. What is the magnitude of the horizontal acceleration of the block?

Relevant equations
V0x=v0cosθ
V0y=v0cosθ
F=ma

The attempt at a solution
Too many to list

Before you can calculate the net horizontal acceleration, you need to find the net Horizontal force on the block. then Newtons second law should work to give you the net horizontal acceleration.

I've seen better worded questions. Since the block appears against a fixed surface (a table?), I'd guess there's a third force (and a fourth if there's gravity). And you just have to assume there are no more unmentioned forces, such as friction.

F1=56.8 N
F2=39.2 N
Weight of the block is 70.56, so the force the table is exerting upward on the block is 70.56 N.

So the net force is 166.56N?

I know that if I divide that by the mass, I will not get the correct answer.

So what's next?

dragon18 said:
Weight of the block is 70.56, so the force the table is exerting upward on the block is 70.56 N.
No. Resolve each force on the block into its horizontal and vertical components. What do you get? What are the accelerations in those directions (using unknowns where appropriate)? So what equations can you write
(Actually, you'll find you don't need to worry about the vertical direction at all, but let's do this thoroughly.)

haruspex said:
No. Resolve each force on the block into its horizontal and vertical components. What do you get? What are the accelerations in those directions (using unknowns where appropriate)? So what equations can you write
(Actually, you'll find you don't need to worry about the vertical direction at all, but let's do this thoroughly.)

I got 13.15N for the horizontal and 53.50N as the vertical. I don't really know if those are correct and I don't understand what to do afterwards.

dragon18 said:
I got 13.15N for the horizontal and 53.50N as the vertical.
That's just adding up the forces in the diagram, right? But as I mentioned, the normal force is missing. What will the acceleration be in the vertical direction? What does that tell you about the normal force?
Given that there are no other horizontal forces, what will the horizontal acceleration be?

In the vertical direction I got 1.91 m/s^2 for acceleration. I think the horizontal acceleration in 5.44 m/s^2.

I am sorry, I'm just very bad at following written directions

dragon18 said:
In the vertical direction I got 1.91 m/s^2 for acceleration. I think the horizontal acceleration in 5.44 m/s^2.
Horizontal sounds about right. For vertical, how is the block going to accelerate through the table?

## What is the formula for calculating horizontal acceleration on a 7.20 kg block with F1 and F2?

The formula for calculating horizontal acceleration is a = (F1 + F2)/m, where F1 and F2 are the individual forces acting on the block and m is the mass of the block.

## What are the units of measurement for the calculated horizontal acceleration?

The units of measurement for horizontal acceleration are meters per second squared (m/s^2).

## Is the direction of the forces important in calculating horizontal acceleration?

Yes, the direction of the forces is important in calculating horizontal acceleration. The direction of the forces determines whether they are acting in the same direction (resulting in a larger acceleration) or in opposite directions (resulting in a smaller acceleration or deceleration).

## Can the horizontal acceleration be negative?

Yes, the horizontal acceleration can be negative if the forces acting on the block are in opposite directions, resulting in deceleration.

## How does the mass of the block affect the horizontal acceleration?

The mass of the block affects the horizontal acceleration by making it smaller if the mass is larger. This is because a larger mass requires more force to accelerate it, according to Newton's second law of motion (F=ma).

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