Recent content by drumercalzone

Thank you for your help! It just seemed too easy!

Homework Statement Using an AC signal generator vs, a transformer with turns ratio n = 1, and a battery VB, sketch a circuit that will generate the output signal vout = vs + VB Homework Equations \frac{V_2}{V_1} = \frac{N_2}{N_1} The Attempt at a Solution Here's my sketch...

Homework Statement a) Determine the impedance of this circuit. b) What is the impedance when \omega = \frac{1}{\sqrt{LC}} Homework Equations The Attempt at a Solution EDIT: I got the Z wrong. It's Z = \frac{L}{C(j{\omega}L - \frac{j}{{\omega}C})} For part b, I'm...

Bah. I don't know why this is eluding me. Here's where I am now: dq= \frac{q}{4{\pi}r^2}da , da=2{\pi}rdr therefore: dq = \frac{q}{2r}dr (Here r is the radius of the slice, I'll use R for radius of the sphere). However I don't think that I have my da right. What's the...

Originally I thought that surface area would come into play, but I think that since we're worried about Current Areas maybe not? I feel like there should be a dq in there somewhere. So maybe two integrals?

Okay, so for the area, I could integrate from 0->R twice to sum all the cross-sectional areas of the sphere: A = \pi r^2 therefore dA = 2{\pi}rdr and A_{total}=2\int_0^R \! 2{\pi}rdr and A= 2{\pi}R^2 Now we have: \vec{\mu} = \frac{q}{T} \frac{2{\pi}R^2}{c} =...

Homework Statement Show for a solid spherical ball of mass m rotating about an axis through its center with a charge q uniformly distributed on the surface of the ball that the magnetic moment \mu is related to the angular momentum \vec{\mu}={\frac{5q}{6mc}}\vec{L} Homework...

Homework Statement Prove that the spherical harmonic wave function \frac{1}{r}e^{i(kr-{\omega}t)} is a solution of the three-dimensional wave equation, where r = (x^2+y^2+z^2)^{\frac{1}{2}} . The proof is easier if spherical coordinates are used. Homework Equations Wave function...

Thank you so much for your help! I'm definitely going to look into the Conductance thing there. It looks like a very valuable tool.

Well let's see: \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} Which I got to: \frac{1}{R_{eq}} = \frac{R_1R_2 + R_1R_3 + R_2R_3}{R_1R_2R_3} Which means: R_{eq} = \frac{R_1R_2R_3}{R_1R_2 + R_1R_3 + R_2R_3} Then I'd plug that in V = IR_{eq} and get: V =...

Thanks for the quick reply! I see where you're getting at - makes the math much simpler, but we haven't covered conductance yet. Is there any other way around the problem, or do I just have to do some nasty algebra?

Homework Statement Hey everyone. I might be overthinking this one, but I thought I'd post it. (sorry for the crappy MS Paint sketch!) I need to find the current through R3 Homework Equations V=IR \SigmaV=0 (around a closed loop) \SigmaI=0 (going into a junction) The Attempt...