Transformer, AC Source, and a Battery

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drumercalzone
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Homework Statement



Using an AC signal generator vs, a transformer with turns ratio n = 1, and a battery VB, sketch a circuit that will generate the output signal vout = vs + VB

Homework Equations



[tex]\frac{V_2}{V_1} = \frac{N_2}{N_1}[/tex]

The Attempt at a Solution


Hand-drawn circuit schematic: an AC source Vs on the left feeds the primary coil of a transformer; the secondary coil on the right connects to a battery with a + sign in series, with output labelled Vout across the terminals.


Here's my sketch, but I feel like I'm missing something conceptually. Because if this were the case, couldn't the battery be on the bottom wire since we're dealing with an AC signal source?
 
drumercalzone said:

Homework Statement



Using an AC signal generator vs, a transformer with turns ratio n = 1, and a battery VB, sketch a circuit that will generate the output signal vout = vs + VB

Homework Equations



[tex]\frac{V_2}{V_1} = \frac{N_2}{N_1}[/tex]

The Attempt at a Solution


Hand-drawn circuit schematic of a transformer: an AC source Vs on the primary side, and on the secondary side a battery with its + terminal at the top and the output labelled Vout across the secondary terminals.


Here's my sketch, but I feel like I'm missing something conceptually. Because if this were the case, couldn't the battery be on the bottom wire since we're dealing with an AC signal source?

Looks fine to me. The battery can go in either the bottom or top leg of the secondary. It will still add a DC offset to the output.
 
Thank you for your help! It just seemed too easy!
 
You are welcome.

One of the things that makes this work in this example, is that the internal resistance of an ideal voltage source is zero. So putting the DC voltage source in series with the transformer does nothing but add an offset voltage.