Recent content by electronicsguy

There are many ways to solve this. The BASIC WAY is to simplify the expression. Let's name the Expression F F = (p+q’+r+s’). (p’+q+r+s’). (p’+q’+r+s’) F = (p + q')(p'+q)(p'+q') + (r+s') ---By factoring out (r+s') F = (pp' + pq + p'q' + qq')(p'+q') + (r+s') ---Multiplying (p + q')(p'+q)...

Glad to help :)

The link given by micromass has everything you need to know and you don't need to know Euler's Formula to understand what he meant. I suggest read (not skim) the link provided by micromass.

I think you misunderstood (3). E=σ/2ε means the Electric Field intensity at a point due to an INFINITE plane charge where σ = Surface Charge Density. It was derived by integration using dE = (dQ/4∏εR^2)aR where aR is the unit vector from charge to point and having R as the distance and using σ =...

1. If it was mentioned in the book that height of cylinder >> diameter of cylinder, (much like a wire), then the top and bottom surface of the cylinder would be negligible. 2. Same as number one but in here, the diameter >> height of cylinder. 3. Electric Field would still emanate from the...

Ok so the uneven force of the atmospheric pressure due to a wide opening does not hold the liquid in tact. How does this have anything to do with the vortex bottle?

By extending the force T, you can see that it will contact point D. So it is like you're applying the force T directly on point D and the lever arm will be BD. Then take the perpendicular component of force T relative to the slope. You can always check. If we assume that BT is perpendicular...

If I hold the top end of a straw filled with water, the water stays in the straw which is due to the atmospheric pressure. How come this effect is not seen in upside down cups? Should the atmospheric pressure keep the liquid inside it within the cup since the other end is closed? Also, the...