Recent content by elizaburlap
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Least Upper Bounds: Find, Exist & Belong to Set
Okay! Thanks!- elizaburlap
- Post #8
- Forum: Calculus and Beyond Homework Help
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Least Upper Bounds: Find, Exist & Belong to Set
This is why I thought that the greatest lower bound was one. Because n=1, 1/n=1. as far as I know n cannot be smaller than one as a natural number. Doesn't this make 1 the greatest lower bound??- elizaburlap
- Post #6
- Forum: Calculus and Beyond Homework Help
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Least Upper Bounds: Find, Exist & Belong to Set
Well, I thought it was, because x has to be a natural number.- elizaburlap
- Post #3
- Forum: Calculus and Beyond Homework Help
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Least Upper Bounds: Find, Exist & Belong to Set
Homework Statement Find the least upper bound and greatest lower bound (if they exist) of the following sets and state whether they belong to the set: a. {1/n:n\in"Natural Number"} b. {x\in"Rational Number":0≤x≤√5 c. {x irrational:√2≤x2} d. {(1/n)+(-1)n:n\in"Natural Number"}...- elizaburlap
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- Bounds
- Replies: 8
- Forum: Calculus and Beyond Homework Help
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Undergrad How Do You Determine Supremum and Infimum Without Graphing?
How would you go about extending it to infinity? In the text it has a few examples that span n from 1 to infinity. Such as, an=n(-1)^n I understand that it does converge, because an approaches 0 as n approaches infinity, but when the equations become more complicated, how to I...- elizaburlap
- Post #4
- Forum: Calculus
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Undergrad How Do You Determine Supremum and Infimum Without Graphing?
In class, we have been introduced to the supremum and infimum concepts and shown them on graphs, but I am wondering how to go about deriving them, and determining if they are part of the set, without actually having to graph them- especially for more complicated sets.- elizaburlap
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- Graphs Supremum
- Replies: 4
- Forum: Calculus
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Induction Proof: Am I on the right track?
Thank you! This was my first attempt at an induction proof, so I wasn't too sure. Oh! I see the x2 now, thanks :)- elizaburlap
- Post #3
- Forum: Calculus and Beyond Homework Help
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Induction Proof: Am I on the right track?
Homework Statement Let a(1)=a(2)=5 and a(n+1)=a(n)+6a(n-1), n≥2 Use induction to prove that a(n)=(3^n)-(-2)^n for n≥1 Homework Equations Not applicable The Attempt at a Solution I have check that a(3) = 5+6·5 = 35 = 3^3-(-2)^3 so it holds for n = 3. The cases n = 1 and n = 2...- elizaburlap
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- Induction Proof Track
- Replies: 3
- Forum: Calculus and Beyond Homework Help