Ah thank you, that's what I forgot.
I'm having issues with this other problem
"A hoop is released from rest at the top of a plane inclined at 16 above horizontal. How long does it take the hoop to roll 16.4 m down the plane?"
Another energy problem.
I believe the equation is...
That was quickly written, I meant to have those masses be different.
-F_fk = 1/2m_1v^2-m_2gh
This equation equates to 1.4m/s which is the correct answer while...
-F_fk = 1/2m_1v^2+1/2Iw^2-m_2gh
this equation which I believe is the correct equation equates to 1.13m/s.
What am I doing...
Homework Statement
In Fig. 9.2, two blocks, of masses 2 kg and 3 kg, are connected by a light string that passes over a pulley of moment of inertia 0.004 kgm^2 and radius 5 cm. The coefficient of friction for the table top is 0.30. The blocks are released from rest. Using energy methods, one...
Homework Statement
Suppose you hold a small ball in contact with, and directly over, the center of a large ball. If you then drop the small ball a short time after dropping the large ball, the small ball rebounds with surprising speed. To show the extreme case, ignore air resistance and suppose...
Homework Statement
A particle moves along the x-axis while acted on by a single conservative force parallel to the x. axis. The force corresponds to the potential-energy function graphed in Fig. 7.45. The particle is released from rest at point A.
[PLAIN]http://k.min.us/ijze8K.png [Broken]...
I think I got it. Can someone check this?
So my potential spring energy is incorrect I believe. In this problem the mass would be stretching the spring out to x length and not d length so the equation should look like this.
mgx = 1/2kx^2
Since k = mg/d I can sub that in.
mgx =...
Work energy question. Fish on a spring.
Question has been changed as I figured it out. New one is on fish and springs
Homework Statement
If a fish is attached to a vertical spring and slowly lowered to its equilibrium position, it is found to stretch the spring by an amount d.
If the...
Okay, so the work friction does is u_k*m*g*s which would be -29.4J as the force is going the opposite of the displacement. Then the second block does mg*s which is 88.2J of work in the positive direction. Together that gives me a network of 58.8J in the positive direction. Now I can equal...
Ah I see, thanks. I have another question I'm having issues with
There is an 8 kg block on a table with a 6 kg block hanging off of a pulley on the end of a table. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the...
Homework Statement
There is an 8 kg block on a table with a 6 kg block hanging off of a pulley on the end of a table. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the 8.00-kg block and the tabletop is 0.250 The blocks are...
Alright so couldn't I just find the total from what I did above, then dividing the power by the velocity to get force and then multiple that by .3 to get teh water resistance? 70% is going forward while the other 30% is water resistance?
EDIT: Hmm that not correct.
I really don't know what...
Homework Statement
The aircraft carrier John F. Kennedy has mass 7.4*10^7kg. When its engines are developing their full power of 280000 hp, the John F. Kennedy travels at its top speed of 35 knots.
If 70% of the power output of the engines is applied to pushing the ship through the water...
Homework Statement
Two blocks with masses 4.00 kg and 8.00 kg are connected by a string and side down a 30.0 inclined plane. The coefficient of kinetic friction between the 4.00kg block and the plane is .25; tha between the 8.00kg block and the plane is .35.
(a) Calculate the acceleration of...