Recent content by f2434427@rmqkr

Alrighty, Well the force applied from gear A, will have an opposite reaction on Gear B. T=F*d F=0.75/0.15 = 5n then applying this force to Gear B. T=F*D = 5 * 0.45 = 2.25 Nm alpha = T/I = 2.25/(10*0.3^2) =2.5 rad/s^2Looks about right to me... hopefully. Logically, first gear would have to...

Ah yes, that would make sense. Forgot to account for the 2nd gears inertia hmm. Dont quite understand what you mean by coupling the masses though

First time posting. Homework Statement Gears A and B, of Masses 4kg and 10kg, respectively, are rotating about their mass centers. The radius of gyration about the axis of rotation is 100mm for A and 300mm for B. A constant couple of C=0.75Nm acts on gear A. Neglecting friction, compute: -...