Dynamics Physics - Acceleration Analysis / Gear Ratios /

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Homework Statement



Gears A and B, of Masses 4kg and 10kg, respectively, are rotating about their mass centers. The radius of gyration about the axis of rotation is 100mm for A and 300mm for B. A constant couple of C=0.75Nm acts on gear A. Neglecting friction, compute:

- Angular Acceleration of each gear
- Tangential contact force between the gears at CMay want to look at attachment for image.

Homework Equations


The Attempt at a Solution


Started with the smaller gear.

Using T=I\alpha , where I=mr^2

Rearrange the equation to get \alpha = 0.75 / (4*0.1^2) = 18.75 rad/s^2

Not to sure how to draw a relationship with the 2nd larger gear. Maybe using w1/w2 = r2/r1 then \alpha = w^2 * r

Thanks,
 

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Welcome to PF;
The applied torque has to accelerate both gears doesn't it?
If this were a linear case, you'd use a free body diagram to couple the masses wouldn't you?
 
Ah yes, that would make sense. Forgot to account for the 2nd gears inertia

hmm. Dont quite understand what you mean by coupling the masses though
 
When you push on one mass, it pushes on the other one .. the masses are said to be coupled ... the motion of one affects the motion of another.
 
Alrighty,

Well the force applied from gear A, will have an opposite reaction on Gear B.

T=F*d

F=0.75/0.15 = 5n

then applying this force to Gear B.

T=F*D = 5 * 0.45 = 2.25 Nm

alpha = T/I = 2.25/(10*0.3^2) =2.5 rad/s^2Looks about right to me... hopefully. Logically, first gear would have to spin faster than the 2nd.
 
That's right - the smaller gear will reach a higher angular velocity in the same time, so must have a higher acceleration. You should be able to see from the relative sizes how the accelerations are related.
 
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