Recent content by fatou123

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    How Do You Calculate the Area Under a Complex Function?

    soz i meant g(x) = (5 + 9x - 2x^2)/((x^2 - 6x + 23)^(3/2)). i still haven't learn how to do integral by substitution with trigonometry yet.
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    How Do You Calculate the Area Under a Complex Function?

    thank you again tiny tim i think i am starting to crack it with a little help well a big one to be honest ! so i gather that the trig substitution might be of the form sqrt a^2 +b^2 x^2 x=a/b tan(theta) so far i found the denominator to be to be sqrt((x-3)^2-14)^5) and i think by using the...
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    How Do You Calculate the Area Under a Complex Function?

    thank you . after completing the square for the bottom i end up with this. y= 100(2x+1)(5-x) ((x-3)^2 -3^2) +23)^5/2) do i have to do the integral by part ?
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    How Do You Calculate the Area Under a Complex Function?

    i am struggling with this question for quite few days now and i am nowhere near to an appropriate solution. The previous ( related) question were regarding the the function g(x)= 5+9x-2x^2 /(x^2 -6x+23)^3/2. i have found the derivatives, the stationary point and also to classify them...
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    Inverse function of a parabola

    thank hallsofivy you have just confirm what i though that theyr were something wrong in my result =. i tackle this equation by comoleting thr squares of a quadratic equations,and i think this is where i got confused by the two result i was looking for! lol the domain of g(x) is given to...
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    Inverse function of a parabola

    from a graph of a function ( i obtained the graphg by doing a translation and y-scaling) g(x)= 1/3(x-2)^2 -3 b (x in [2:5]) i can see that g is increasing and so it is a one-one function and an image set is [-3;0]. so therefore the function g has an universe function g^-1 . so i can find...
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