Recent content by fishingaddictr

Homework Statement 1 625g iron block is heared to 352 C is placed in an insulate container (of negligible heat capacity) containing 40g of water at 15 C. what is the equilibrium temp of this system? if your answer is 100 C, determine the amount of water that has vaporized. Homework...

ahhh ok.. i knew i missed sumthin important so ... .3606x25.2x2090= 18992.0808 then i use the latent heat of fusion for water and get .3606x(33.5x10^5)=120801 combine them 18992.0808+120801= 139793.0808 --> 1.4x10^5 thank you gokul

anyone? help please?

Homework Statement How much energy is necessary to completely melt an ice cube of mass 360.6grams that is initially at a temp of -25.2 degrees celsius. Homework Equations im thinkin i should use specific heat equation? is that right? c=Q/m(change of temp) 2090=Q/.36069(25.2) The...

yup yup. thought it was tryin to trick me by askin the temp of beginnin and end like it was going to be two different values.

and for the work i get 1670.42j

im getting .332 for the temperature.

so i wouldn't use pv=nrt?

Suppose 145 moles of a monatomic ideal gas undergo an isothermal expansion from 1.00m^3 to 4.00m^3, as shown in figure. what is the temp at the beginning and end of this process? how much work is done by the gas during the expansion? http://www.physics.brocku.ca/Courses/1p23/images/FG18_24.JPG...

pressure is greater in the bigger area with less fluid speed. the greater fluid speed has the least pressure.

Water flows throgh a horizontal tube of diameter 2.8cm that is joined to a second horizontal tube of diameter 1.6cm. the pressure difference between the tubes is 7.5kPa. which tube has the higher pressure flow? which tube has the higher speed flow? find the speed of flow in the first tube...

i think i got it.. it takes 1.629 seconds for one oscillation.. we're solving for number of oscillations per min. so divide 60 by 1.629.. would be 36.8 oscillations per minute? correct? anyone?

still reviewing my test and I am having trouble. A pendulum consists of a bob of mass 0.14kg at the end of a light string of length 0.66 meters, whose other end is fixed. the number of oscillations executed by the pendulum each minute is...? so far this is what I've got L= (gT^2) /...

oh ok. i got it since the mass would cancel out i got r1^2*v1=r2^2*v2 with the answer 73.46radians per second. is that correct?

thats what i was thinking.. so i would set them equal.. what would the moment of inertia be for this case?