Solving for T in a Simple Pendulum: Troubleshooting and Tips

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SUMMARY

The discussion focuses on calculating the period (T) of a simple pendulum with a mass of 0.14 kg and a string length of 0.66 meters. The formula used is L = (gT^2) / (4π²), leading to a calculated period of 1.629 seconds for one complete oscillation. To determine the number of oscillations per minute, the user divides 60 by the period, resulting in approximately 36.8 oscillations per minute. The calculation is confirmed by other participants in the discussion.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Familiarity with the formula for the period of a pendulum
  • Basic knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Ability to perform unit conversions and basic arithmetic
NEXT STEPS
  • Study the effects of varying string length on pendulum period
  • Explore the concept of damping in pendulum motion
  • Learn about the mathematical derivation of the pendulum formula
  • Investigate the relationship between mass and oscillation frequency
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in the principles of oscillatory motion and pendulum dynamics.

fishingaddictr
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still reviewing my test and I am having trouble.

A pendulum consists of a bob of mass 0.14kg at the end of a light string of length 0.66 meters, whose other end is fixed. the number of oscillations executed by the pendulum each minute is...?

so far this is what I've got

L= (gT^2) / (4pi^2) solve for T, i get 1.629 seconds..

where do i go from here?
 
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i think i got it.. it takes 1.629 seconds for one oscillation.. we're solving for number of oscillations per min. so divide 60 by 1.629.. would be 36.8 oscillations per minute?

correct? anyone?
 
fishingaddictr said:
i think i got it.. it takes 1.629 seconds for one oscillation.. we're solving for number of oscillations per min. so divide 60 by 1.629.. would be 36.8 oscillations per minute?

correct? anyone?
Looks like you got it. A useful bit of trivia.. when L = 1 meter the period is very close to 2 seconds.
 

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