Calculating Energy Needed to Melt an Ice Cube

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To calculate the energy needed to melt a 360.6-gram ice cube at -25.2 degrees Celsius, the specific heat equation is used to first determine the energy required to raise the temperature of the ice to 0 degrees Celsius. This initial calculation yields approximately 18,992 joules. Next, the latent heat of fusion is applied to convert the ice at 0 degrees Celsius into water, requiring an additional 120,801 joules. Combining these two energy values results in a total of approximately 139,793 joules, or 1.40 x 10^5 joules. Understanding both specific heat and latent heat is crucial for accurate energy calculations in phase changes.
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Homework Statement


How much energy is necessary to completely melt an ice cube of mass 360.6grams that is initially at a temp of -25.2 degrees celsius.


Homework Equations


im thinkin i should use specific heat equation? is that right?
c=Q/m(change of temp)
2090=Q/.36069(25.2)

The Attempt at a Solution


Q= 18992
i kno its wrong but I am not sure what approach i need to take in finding the correct answer.

the correct answer is 1.40x10^5
 
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anyone? help please?
 
You've done one part of the calculation. You've found the energy it takes to heat the ice from -25.2C to 0C, but it's still ice at 0C. You now need to convert this ice into water. How much energy does it take to do that?

Look up the what the term 'Latent Heat' means.
 
ahhh ok.. i knew i missed sumthin important

so ... .3606x25.2x2090= 18992.0808
then i use the latent heat of fusion for water and get .3606x(33.5x10^5)=120801

combine them 18992.0808+120801= 139793.0808 --> 1.4x10^5

thank you gokul
 

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