Recent content by fobbz

I know it is 20 000.5 because what changed was only the refractive index - the m order value did not change. So because it's now a minimum, (m+1/2) wavelengths would appear?

I understand everything up to B). I believe Bernoulli's is applicable here, however I am unsure as to whether or not the pressure before the tube (pgh) is the same or different as the pressure at the tube pgh +p0. I ask the same question for the opposite end of the tube. I know that pressure...

well v=fλ. So if the wavelength is λ=c/f=(3E8 m/s) /(6E14 m) , λ=5E-7 m So in 1 cm, 1 cm / 5E-7 = 20 000 wavelengths? Okay that makes sense... b) So next if the maxima changes to a minima, that means that an extra half wavelength is now being sent out making it destructive? So there...

I have attached the problem as the image is needed for the question. a) Basically, from what I understand the wave is being split, thus each chamber receives the total number of wavelengths/2. The chambers, however are vacuums, so the number of wavelengths passing in doesn't change right...

I'm sorry but I think your calculations are a bit advanced for me... I'm just a senior in high school and we've never seen those types of equations.. Regarding the movement of electrons however I believe you can help me with. I don't understand what's happening physically to the electrons...

Homework Statement http://img716.imageshack.us/img716/7692/picture8sj.png Homework Equations ΔEp=QV Ek=0.5mv2The Attempt at a Solution I'm making sure I understand what's going on here. Please bare with me. ΔEp = Ek .5mv2 = Q(1200+V) Solving for V, I get -642V. In a nutshell, is this what...

I'm looking for an A-level physics exam, from any year, a whole exam. I'd like to compare the difficulty to the exams we see here in BC Canada. Please if you have sample exam share it! Also if this is the incorrect forum please move my post, - I wasn't sure where to put it elsewhere! Thanks

How do you know that the first ball will bounce backwards?

Homework Statement A ball of mass 5.0kg moving at a speed of 5.0m/s has a head on collision with a stationary bal of mass 6.0kg. If the collision were perfectly elastic what would be the speeds of the two balls after the collision? Homework Equations P = mv KE = 0.5mv2 The Attempt at...

oh my god! I'm such an idiot. I saw he 12V battery and wrote in an extra resistor. Thanks. hahaha.

I'm sorry but I do not understand. In the preceding diagrams the 12 resistor is there... why should it no longer be there? I must be missing something.

Homework Statement Breakdown, and find the total resistance for this circuit. Homework Equations V=IR Parallel Circuits - 1/Rtot = 1/R1 + 1/R2 ... Series Circuits - Rtot = R1 + R2 The Attempt at a Solution http://img696.imageshack.us/img696/4176/centralkootenayj2011122.jpg...

Oh, I now see the arrow you're referring to. That was a silly error, due to the net force the 20kg block would be successful in accelerating downwards. Sorry about that arrow.Thanks though guys!

Fair enough, I see your point on the direction. As you point out, the blocks are going up while the 20kg block is going down, so what is correct for the acceleration? Would it be correct to say that the 20kg block accelerates at 4.26m/s2 [down], but the other blocks accelerate at 4.26m/s2 [up] ...

Homework Statement In the diagram below find the 1) acceleration of the system 2) T1 and T2 The ramp is angled 35degrees to the horizontal and coeff of friction is 0.15 Homework Equations The image at the top is the problem's figure...