Recent content by Foopyblue

The problem is indeed sin(2x). It's really giving me a headache.

Homework Statement Sin2x-cosx=1 Solve for all x values between [0,2pi) Homework Equations Sin2x=2sinxcosx The Attempt at a Solution [/B] 2sinxcosx-cosx=1 cosx(2sinx-1)=1 I don't know what to do after this. It doesn't equal 0 so I can't set each factor equal to 0

The textbook and I both agree that there was a change in height of 10 m, but where we differ is that they are calculating the potential energy from the height above the ground(30m) while I am calculating the potential energy from the height above point C(10m). That's why their ratio is different...

I hate to bother you Arjun but I'm having trouble reading it because of the quality, do you have another picture you could upload?

If I set my reference height of C as ground level, is that not the total energy of the system? It has no Kinetic at point A, all Potential, right?

Homework Statement A roller coaster at an amusement park is at rest on top of a 30 m hill (point A). The car starts to roll down the hill and reaches point B which is 10 m above the ground, and then rolls up the track to point C, which is 20 m above the ground. (A) A student assumes no energy...

I tried thinking about this more deeply. The Law of Conservation of energy states that the total energy of an isolated system is conserved so that its change is zero. If I choose my system to be the Earth, the inclined plane, and the block, then for this problem, it is indeed isolated. This...

So if I chose my system to be just the block, I would only have to worry about Kinetic Energy and this is why Work=ΔK works?

This is what my textbook says for each equation. Work=ΔE The total energy of a system changes by the amount of work done on it. Another way to right the equation above is by listing the specific types of energies found in the system. The only energies I found in this system were Kinetic...

Homework Statement A box slides down an inclined plane (angle = 37*). The mass of the block is 35 kg, the coefficient of kinetic friction between the box and the ramp is 0.3, and the length of the ramp is 8 m. If it starts from rest at the top of the ramp, with what speed does it reach the...

Wow. It finally makes sense. Thank you so much!

So basically does that mean that where ever you are in the system, the force is going to be constant? Is this why they can refer to the force without any subscript, because they don't have to specify since it's the same everywhere?

It would be just k2x2. The applied force does not exert a force on the first spring. Only the 2nd spring exerts a force on the 1st spring which is equal to the applied force.

The amount my hand moves is equal to the x in F=kx.

They are also equal?