Recent content by freutel

Ok, so the force balance at disk A is the gravitational force downwards and an equal tension force upwards. There will be torque clockwise because the tension force is excerted at distance r from the rotation axis. Just as I solved it earlier i get for acceleration downwards acm=2/3g. Then will...

Homework Statement The question is to specify all forces and constraints that are applied in a system of a two-seat merry go round model in terms of the generalised coordinates - and their type (e.g. geometric, kinetic). http://i.imgur.com/FQ7PJyg.png The system is modeled as central...

Homework Statement Two identical disks with mass m and radius r are connected via a massless wire of length L which is winded up around both disks. Disk B is connected to the ceiling and is free to rotate around its axis. Disk A is besides disk B and will fall due to the gravitational force...

Yes! I made a little mistake, I forgot to set the boundaries from 0 to T but now I got it! Thank you very much, TSny!

I know you are not supposed to give full answers but I really cannot find that missing M. Can you please help me?

I always fail to see the easiest way to solve the problem.. Ok so I did Vt=dx/dt which gives x=((MwagonV)/C)*ln(Mwagon+Ct) The x is of course L so I isolated everything from the natural log which gives LC/(MwagonV)=ln(Mwagon+Ct) This results in Mwagon+Ct=exp(CL/MwagonV). Now I get for t -->...

Homework Statement A train wagon of mass M moves on a rail with constant velocity V (without friction). It passes a sand hopper which pours sand in the wagon at constant rate C [kg/s]. The sand falls vertically so it does not transfer any horizontal momentum to the wagon. The length of the...

Wow, I would seriously have never come up with that. Should have paid more attention in class. So I looked it up how to solve a geometric series (because I never quite learned how to do it in school) so i came up with this T=t0 + t1 + t2 + t3 +... + tn. T=(2V/g) + (2V/g)*√k + (2V/g)*√k2 +...

It's power series right? With the power of k constantly increasing. I honestly do not know and I'm just saying stuff.

Now i came up with that the total time it will take is T=t0 + Σtn with n=1, 2, 3,...,. The energy that is lost after every bounce is also ½mv2(1-kn). The number of bounces needed is when kn approaches zero. That's all I know. Now that I think of it, it may be impossible to know what n is with...

Homework Statement A ball, which is launched in the air with velocity V, has inelastic collisions with the floor: the kinetic energy after each collision is k times the kinetic energy before the collision, where k<1. Assume that the gravitational acceleration is constant: g [m/s^2]. I was asked...