Recent content by futron

Got it. Thanks for your help! ~Futron

It is perpendicular relative to the magnetic field. How would I then calculate that into the Fnet equation? Thanks. ~Futron

Wouldn't Fnet be the sum if they are both pointed the same direction? ~Futron

"A magnetic field has a magnitude of 1.2 x 10-3 T, and an electric field has a magnitude of 5.1 x 10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 3.2 x 10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net...

Thanks! I was jumbling too many equations together at once but that made it much clearer.

Alright, I tried using EPEf-EPEi=(1/2)mv^2 where EPEf=(5x10^-6)((9*10^9)*(-5*10^-6)/0.4)) and EPEi=(5*10^-6)x((9x10^9)(-5x10^-6)/0.8)), but that gives 5.43m/s, which is not the correct answer.

Thanks, but I'm still not getting the correct answer. Which charge should I use for q in EPE=qE\Delta x , and once I get that, would it simply be a matter of solving EPE_f-EPE_i=(1/2)mv^2 ?

So if I have EPE_a-EPE_b=q_0(V_A-V_B) where V=kQ/r , how would I then find the difference between the two when the distance is halved?

Alright, I tried using EPEi=EPEf+(1/2)mv^2 where EPE=q0*(Va-Vb), but that doesn't seem to work. Any ideas?

"Two particles each have a mass of 6.1*10-3 kg. One has a charge of +5.0*10-6 C, and the other has a charge of -5.0*10-6 C. They are initially held at rest at a distance of 0.80 m apart. Both are then released and accelerate toward each other. How fast is each particle moving when the separation...

I've E=(1/2)mv^2+(1/2)Iw^2+mgh, but I'm still unclear as to how theta fits into this equation.

Can anyone help me on the following problem? I'm not sure how to relate the 90-degree rotation with the rest of what's being asked. A thin uniform rod is initially positioned in the vertical direction, with its lower end attached to a frictionless axis that is mounted on the floor. The rod...