- #1
futron
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"A magnetic field has a magnitude of 1.2 x 10-3 T, and an electric field has a magnitude of 5.1 x 10^3 N/C. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 3.2 x 10^6 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge."
Using the crossed magnetic and electric field equation, wouldn't the net force be F=qE+qvB? I resolved it to 0.01609N, which isn't the correct answer. Any ideas?
~Futron
Using the crossed magnetic and electric field equation, wouldn't the net force be F=qE+qvB? I resolved it to 0.01609N, which isn't the correct answer. Any ideas?
~Futron