Recent content by gabloammar

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    Simple Magnetic Field Question.

    Thanks for the reply! That's the right hand rule then isn't it? And I wanted to ask, what's the difference between the right hand grip rule and the right hand rule?
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    Simple Magnetic Field Question.

    Homework Statement In the attachment. Homework Equations The left hand rule. [and the right hand grip rule maybe?] The Attempt at a Solution Aren't we supposed to have two of three things [out of direction of motion, direction of current, and direction of magnetic field] to find...
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    Magnetic field affecting an alpha and a beta particle.

    r = mv/BQ? no? For an α-particle, m would be (1840x4) times greater than for a β-particle [because it's a helium nucleus and a β-particle is an electron]. v is the same for both particles. B is also the same. Q, the charge, on the other hand, will be positive and negative for alpha and beta...
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    Oh my. This is magic. [well actually it's logic but the way it all just worked out was magic!] Thank you! [I equalled the gain of the silver to the loss of the gold and got a value for temperature from there and I added that to the melting point of the gold. I hope that's correct.]
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    So the heat gained by the silver is supposed to be... 0.05m x 235 x 900 + 0.05m x 105000 (keeping everything in Joules) + 0.05m x 235 x 100? [by the way I had absolutely NO idea about using the latent heat. I thought they'd put it in the question just for confusion's sake.] And all this...
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    Isn't that supposed to be 0.05m x 235 x 1040? It can't be anything else can it?
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    So the heat lost by the gold should be 0.95m x 129 x Δθ right? And the heat lost by the gold is the heat gained by the silver. [at least that's what I could make out from the hint] Once more, I'm stuck. So I've got a formula for the heat lost by the gold. What should I be doing with that or...
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    Magnetic field affecting an alpha and a beta particle.

    Homework Statement An \alpha-particle and a β-particle are both traveling along the same path at a speed of 1.5x106 ms-1. They then enter a region of uniform magnetic field. The field is a square with sides of 1 cm. The magnetic field is normal to the path of the particles and is into...
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    Umm, this is kind of embarrassing [then again a person should never be embarrassed to admit their own weakness], but, the ONLY thing I've been able to think of is that the initial temperature of the silver is 300 K, and that that has something to do with the melting point of gold is 1340 K and...
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    Let me give it a spin and get back to you on that. Thanks!
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    Question on Thermal Physics. [it feels impossibly difficult to me]

    Homework Statement This question has got me REALLY confused. I'll be thankful for any help. I don't even know where to start, though I'll mention what my thoughts were. Q. A jeweller wishes to harden a sample of pure gold by mixing it with some silver so that the mixture contains 5.0% silver...
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    Understanding the Virtual Earth Approximation in Op-Amps

    Homework Statement I'm studying op-amps at the moment, and I came across a statement and I don't understand it. 'To understand how the inverting amplifier works, you need to understand the concept of the virtual Earth approximation. In this approximation the potential at the inverting input...
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    Can anyone PLEASE tell me how a current balance works?

    Right, right, and right. Thank you SO much for your help. Life saver! Good day. :)
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    Can anyone PLEASE tell me how a current balance works?

    Haha, I took the 0.02 g correctly, I just didn't convert it correctly. Used x10-2, must've pressed the wrong button. Got the correct answer! But does this mean that I'm supposed to use the length of the wire that only passes through the magnet? [because only that can obviously be 5 cm]
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    Can anyone PLEASE tell me how a current balance works?

    Using 1.962x10-3 N for force, 0.50 A for current, and 5x10-2 m for length, I get 7.85x10-2 T, which isn't the right answer. :( How'd you get it right?
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