Recent content by gendoikari87

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    Curious: Magnetic bullet question

    No, not the ferrous metal ones that magnets stick to. My question pertains to what would happen if you shot a neodymium magnet out of a shotgun. I've see a video where they do it and they stick together but what about their effects on electronics? If you hit it and they didn't penetrate...
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    Integrating a squared velocity

    Nah I was taking it at 100 meters. It was unit problem with the Drag coefficient converting from BC.
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    Integrating a squared velocity

    Yup, it was the BC, or at least i think, I'll have to check it out some more. Thanks for the help.
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    Integrating a squared velocity

    Problem is the solution with the log function is giving me ansers of several thousand years for a flight time This is where I get K, it's everything but the V squared term and divided by mass. Edit: hold on, it could be my drag co-efficient is f'ed up.
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    Integrating a squared velocity

    call it intuition. I'll have to do unit analysis though. K I think has a dimention but IIRC it's inverse mass I'll check after while.
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    Integrating a squared velocity

    Cool, so I've solved for V: V= 1/(KT+1/Vi) Wolfram integrates it as Log(KTVi+1)/K=X That doesn't seem right, If I simply integrate KT+1/Vi with respect to X (because 1/v is dT/dX) I get KTX+X/VI=T Which becomes X/(Vi-KXVi)=T
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    Integrating a squared velocity

    So this gives me: 1/kv+vi=T correct? From here I changed the V to dx/dt but since it is 1/v it becomes (1/k)*dt/dx+Vi=T Multiplying by dx I then get (1/k)dt+Vidx=Tdx Integrating yields T/k +ViX=T*X (accounting initial time and distance as zero) But that just seems wrong... Breaking...
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    Integrating a squared velocity

    ... that's just initial velocity is it not?
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    Integrating a squared velocity

    Okay I'm working on making a ballistics calculator and I need to know how to integrate this. To get velocity, and ultimately to get time of flight. So that I can use that to determine drop with an angle of 0.
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    How Do You Integrate dy/dt with Respect to y in Ballistic Equations?

    actually I re wrote the thing in an easier form but it gets messy if you just use separation of variables dv/dt=-fV^2-9.8 I can't remember how to do this using ODE, any help?
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    How Do You Integrate dy/dt with Respect to y in Ballistic Equations?

    http://latex.codecogs.com/gif.latex?(d^2Y)/(dTdY)=%20-c(dY/dT)-9.8(dT/dY) basically how do you integrate dy/dt with respect to y, I know dy/dt integrated with respect to t is simply Y, but the other I have no idea. background: C is a constant that is a function of air pressure and is from the...
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