Recent content by GeneralOJB
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Graduate The formula pV=1/3Nm(c_rms)^2 in non cuboids
Does pV = \dfrac 1 3 N m \left(c_{rms}\right)^2 apply in containers that aren't cuboids? The derivation I have seen uses a cuboid container so I'm not sure if or how this can be generalised.- GeneralOJB
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- Formula
- Replies: 2
- Forum: Classical Physics
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Why is William & Mary ranked so low?
Don't pay attention to rankings; they're meaningless. Just have a look at the 2015 UK Mathematics league tables according to The Guardian. http://www.theguardian.com/education/ng-interactive/2014/jun/03/university-guide-2015-league-table-for-mathematics I suppose firming Cambridge and...- GeneralOJB
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- Forum: STEM Academic Advising
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Loomis "Advanced Calculus" and Baby Rudin
My money is on Rudin.- GeneralOJB
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- Forum: Science and Math Textbooks
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Which Math Book Should I Get for Multivariable Calculus?
Yes, I was planning on doing that, I thought it might be quite difficult to learn it straight from Rudin though. I'll see how it goes.- GeneralOJB
- Post #3
- Forum: Science and Math Textbooks
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Which Math Book Should I Get for Multivariable Calculus?
I am currently reading baby Rudin, but I only know single-variable calculus at the moment, so I think it would be a good idea to learn the multi-variable stuff non-rigorously before I do the analysis in Rudin (chapters 9-11). So I was thinking of either getting one of the many 'Mathematical...- GeneralOJB
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- Calculus Multivariable Multivariable calculus
- Replies: 4
- Forum: Science and Math Textbooks
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Circular Motion: Find an Expression for Mass M
Yes, I would have picked that in the exam, but the question is still wrong. It can't be exactly horizontal if there is no vertical force to balance gravity.- GeneralOJB
- Post #10
- Forum: Introductory Physics Homework Help
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Circular Motion: Find an Expression for Mass M
Indeed. If it is a mistake, then it's shocking that it made its way to an A level exam. Source: http://filestore.aqa.org.uk/subjects/AQA-PHYA4-1-QP-JUN12.PDF (question 6)- GeneralOJB
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- Forum: Introductory Physics Homework Help
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Circular Motion: Find an Expression for Mass M
What's interesting is the "correct" answer is \dfrac{mv^2}{rg}, according to the exam board AQA.- GeneralOJB
- Post #5
- Forum: Introductory Physics Homework Help
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Circular Motion: Find an Expression for Mass M
Yes, only in vertical equilibrium. Maybe M could be moving in a horizontal circle, though we aren't told that it is.- GeneralOJB
- Post #3
- Forum: Introductory Physics Homework Help
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Circular Motion: Find an Expression for Mass M
Homework Statement The diagram shows a smooth thin tube through which passes a string with masses m and M attached to its ends. The tube is moved so that the mass m travels in a horizontal circle of radius r at constant speed v http://quickpic.info/z/yb.jpg Find an expression for M...- GeneralOJB
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- Circular Circular motion Motion
- Replies: 10
- Forum: Introductory Physics Homework Help
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Calculus books used at top universities
Cambridge University recommend Calculus by Spivak/Apostol, then Rudin, but they seem to prefer Burkill for some reason.- GeneralOJB
- Post #7
- Forum: Science and Math Textbooks
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High School Can Fleming's Right Hand Rule Be Used When Magnet Moves Parallel to Coil?
I was told that the field is from north to south, so is that not really true then? It seems the field is both perpendicular and parallel from that diagram. Also how can I use the left hand rule to determine the direction of current in this case if the field is going in infinitely many different...- GeneralOJB
- Post #9
- Forum: Electromagnetism
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High School Can Fleming's Right Hand Rule Be Used When Magnet Moves Parallel to Coil?
Yes (I presume so).- GeneralOJB
- Post #7
- Forum: Electromagnetism
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High School Can Fleming's Right Hand Rule Be Used When Magnet Moves Parallel to Coil?
The south is on the other end of the magnet, above the north.- GeneralOJB
- Post #5
- Forum: Electromagnetism
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High School Can Fleming's Right Hand Rule Be Used When Magnet Moves Parallel to Coil?
This is what is confusing me then. Consider a set-up like this: The magnet field points up (north to south) and the movement is also vertical, so the field and movement are parallel.- GeneralOJB
- Post #3
- Forum: Electromagnetism