Recent content by gerardpc

I've read a solution of a problem, in which there are two different gases in a container, initally at equilibrium and separated by an adiabatic fix wall. At some time, this wall is changed by a diathermic mobile wall, so the equilibrium point changes. You have to find the final state of the...

Ok. What about this: Lower chamber: \Delta U_1 = Q_{stirrer} - Q_{up} + p\Delta V So using the expression for the internal energy and the constant volume: 2R\Delta T = 500 - Q_{up} Upper chamber: \Delta U_2 = Q_{up} - p\Delta V So: 4R\Delta T = Q_{up} - p_0\Delta V Adding up these...

Homework Statement We have a cylindrical container filled with a gas: the container has an upper compartment with 2 moles of this gas, and another compartment below with 1 mole of the same gas, separated by a diathermic boundary, and also has an adiabatic mobile plunger over the upper...

Well, I'm not sure of the initial condition, that's why I asked ;) I guess it must be zero internal energy when temperature is zero, so then we can drop de deltas.

Observation: I changed a little the statement of the problem, as I noticed I had additional constraints. Now to the problem: I have found the equation (which I didn't remember...) dU =C_{V}dT +\left[T\left(\frac{\partial p}{\partial T}\right)_{V} - p\right]dV So with the equation of...

Given the following equation of state and C_p = 3R, find the equation of the internal energy in terms of T and V p(V-b) = RT Any clues? I can use also the specific heat at constant pressure or volume. Thanks!

Thank you! Any other recommendations (specially with any pdf or .djvu i can find online, with notes)?

Hello everybody! This is my first thread and I'm just kind of discovering the forum. If I should make a presentation or should have posted this thread somwhere else, let me know please! I have plenty of books and notes about a first course in Thermodynamics, but I'm having a bit of trouble when...