When we say potential difference what do we mean? My textbook defines potential difference as the work required to move a unit of electric charge from point b to point a.
Homework Statement
The work done by an external force to move a -8.5μC charge from point A to point b is 15x10^-4 J. If the charge was started from rest and had 4.82x10^-4 J of kinetic energy when it reached point b, what must be the potential difference between a and b
Homework Equations...
Homework Statement
If 2.00 m3 of water at 0°C is frozen and cooled to -25°C by being in contact with a great deal of ice at -25°C, what would be the total change in entropy of the process?
Homework Equations
ΔS=Q/T Q=mL Q=mcΔT
The Attempt at a Solution
2000 * 4190 * ln...
I solved the problem and have the correct answer just not sure about something.
Question:What will be the equilibrium temperature when a 274 g block of copper at 317°C is placed in a 137 g aluminum calorimeter cup containing 829 g of water at 13.0°C?
So heat lost by copper = heat gained...
Calculate the difference in pressure between the top and bottom surfaces of a cube of size 10x10x10 cm at a depth of 20 cm in water. At 100 cm?
I know that P=F/A . and in this case force is referring to buoyant force so F=ρgV. And the density of water is just 1000 kg/m^3. And the area of the...
i see that the equation for find angular acceleration was derived from ω^2=ω°^2+2αt. But why can't the formula ω=ω°+αt be used. I noticed that when i used the first formula i ended up with -305/((2∏)(53.8)) = -.9 which is correct but when i used the second formula I got
-.073 which is...
I understand how the angular velocity was gotten, and why the amount of revolutions it took to travel 115 m was just 115/circumference of wheel. But why would radians need to be configured to find the angular acceleration? I thought angular acceleration was Δω/τ? And why is 2(thetasymbol) being...
Consider the following two-step process. Heat is allowed to flowout of an ideal gas at constant volume so that its pressure dropsfrom PA = 2.7 atmto 1.4 atm. Then the gas expands at constant pressure, from avolume of 6.8 L to VC = 13.1 L where the temperature reaches its originalvalue. See Fig...
My answer is 12.9 grams, and the correct answer is supposed to be 11.9 grams. I cannot figure out why? Note. the answer i got is 12.9, and not 11.06. I know for this situation, the heat absorbed by the ice equals the heat lost by the water and aluminum, and since there is a phase change from a...