Recent content by Gnall

Oh finally! :) Thank you so much sir, I'm very apreciated.

Oh, yes you are totally right. kQq/R + 1/2mvsquare = 0+0? Is that true? :)

So, Ep1 + Ek1 = Ep2 + Ek2 so, kQq/R + 0 = 0 + 1/2mVsquare Is that true?

Question says Sorry actually I wanted to mean E=qV=kqQ/R instead of V. So I should equalize qV to 1/2mVsquare?

Besides, question says ignore the gravitational force.

Yes but I don't have any idea except that. Should I use F=q.E?

Yes actually. I thought E=qV Then V is kQ/R Kinetic energy is 1/2mVsquare So maybe I can equalize V and kinetic energy?

Understood. So what about the third question? How can I solve?

Oh okay. So the equation is the same except the sign of the second charge?

So how to make electric potential zero at P?

And to make the potential zero at the point P, there should be electric potential at opposite (-y)direction due to the charged particle at (x,y)=(0,L) So how to make electric potential zero at P?

The direction of electric potential due to the semicircle is in +y direction. Because the Vx components will cancel due to the symmetry. Like in the image.

Because, the electric potential due to the semicircle at P point is (kQ/R) and, due to the q charge is (kq/L). So I equalized them. Is that wrong for electric potential?

For the b following: kQ/R=kq/L L=πR kQ/R=kq/πR πQ=q

Thank you so much :)