What does the normal force have to do with this problem? Although the rope is at an angle, the box remains parallel with the x-axis, so f_gravity = 500N would be equivalent, but opposite direction, to the normal, but again I don't see how this applies in the context of my problem.
If you could...
Now, I'd have to be using Newton's second law, here.
Since there is no acceleration on the y axis: sum of forces_y = ma = 0
Now, as for the forces on the x axis, I thought I would need to do something like this, to find the tension of the rope. Let T = tension of rope.
As the box...
My next project is to build a simple TEA nitrogen laser, as seen here: http://photonics.tfp.uni-karlsruhe.de/1/a-homemade-uv-laser.html
Would it be acceptable to substitute two strontium titanate ceramic caps, each rated 50KVDC @ 910pf, in place of the suggested aluminum foil / plastic...
This past weekend, for fun, I made a pneumatic air cannon, using compressed air to shoot out a small projectile at very high velocity. I'd post my video, but I have not made 15 posts on this forum.
What I need to do is find as close as I can to the actual initial
velocity of a projectile...
I know, I just can't seem to apply it in the context of this problem...
I know that a(t)=v'(t) and there is some point is [0,S] where (S - 0 ) / (T - 0 ) = (4S) / (T^2 )
I know the magnitude of acceleration is the slope of the tangent at a point on a speed-time graph.
Any other hints for...
The problem is given in its entirety. My thought is that a car can't go from point A to point B without ever accelerating, so initial velocity = 0. I believe I would do it using the Mean Value Theorem, to prove that there exists a mag of acceleration equal to 4S/T^2 somewhere between point A and B
Going a distance S in time T, prove at some instant the magnitude of the acceleration of the car is (4S)/(T^2)
I have thought a lot about the problem and how I would go about proving it. Would using the Mean Value Theorem be the best way?
I was thinking that I could take two times A and B...