Prove magnitude of acceleration.

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Homework Help Overview

The problem involves proving the magnitude of acceleration of a car traveling a distance S in time T, specifically showing that the acceleration is (4S)/(T^2) at some instant. The subject area relates to kinematics and the application of calculus, particularly the Mean Value Theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster considers using the Mean Value Theorem and discusses the implications of taking two times during the trip. They also contemplate an epsilon-delta proof to approach the desired acceleration value. Some participants question the completeness of the problem statement, particularly regarding initial conditions and constant speed scenarios. Others suggest integrating acceleration to analyze the relationship between acceleration and distance over time.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations and approaches to the problem. Some guidance has been offered regarding the Mean Value Theorem, but there is no explicit consensus on the best method to prove the statement. Participants are actively questioning assumptions and seeking hints rather than complete solutions.

Contextual Notes

There are discussions about the initial conditions of the car's motion, such as whether it starts from rest or maintains a constant speed. These assumptions are critical to the problem but remain under debate.

guipenguin
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Going a distance S in time T, prove at some instant the magnitude of the acceleration of the car is (4S)/(T^2)

I have thought a lot about the problem and how I would go about proving it. Would using the Mean Value Theorem be the best way?

I was thinking that I could take two times A and B during the trip, and according to the MVT there exists another time c such that v'(c) <= (v(b) - v(a) ) / (b - a )

I also thought about doing an epsilon-delta proof to state that as (b - a) approaches T, (v(b) - v(a) ) / (b - a ) would approach a value that was equal to or greater than (4S)/(T^2).

I am not sure what to do to prove this. Any suggestions would be great!
 
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There is something missing in the statement of the problem. For example if the car is going at a constant speed S/T, then the acceleration will always be 0.
 
mathman said:
There is something missing in the statement of the problem. For example if the car is going at a constant speed S/T, then the acceleration will always be 0.

The problem is given in its entirety. My thought is that a car can't go from point A to point B without ever accelerating, so initial velocity = 0. I believe I would do it using the Mean Value Theorem, to prove that there exists a mag of acceleration equal to 4S/T^2 somewhere between point A and B
 
Last edited:
John Creighto said:

I know, I just can't seem to apply it in the context of this problem...

I know that a(t)=v'(t) and there is some point is [0,S] where (S - 0 ) / (T - 0 ) = (4S) / (T^2 )

I know the magnitude of acceleration is the slope of the tangent at a point on a speed-time graph.

Any other hints for setting up a proof using the MV theorem? Or maybe a better way? I can't have someone work it all out for me, I just ask for any hints or suggestions.

Thanks!
 
Are we assuming it starts from rest? How about just integrate the acceleration given and show that if the acceleration is less then that value then there is not enough acceleration to cover the distance in time.
 

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