Recent content by .hacker//Kazu

I see. Thank you so much. I was always confused by why there were brackets sometimes. So if there are no brackets around the integer, the power does not affect it and it stays the same, but if there is a bracket, the power affects it, even power being positive, odd being negative. I think I...

They did teach me. I just never really understood me. But I do now, so thanks for your troubles. :D

Evaluate and express as a fraction in lowest terms -3 to the power of 4 + (-3)to the power of 3 - (-3)to the power of 2. (I apoligize...I don't know how to type powers on the computer...>_<) I tried to evaluate it like it told me to...so I ended up with 81-27+9 =63 Yet when I...

I undestand now. Thank you very much for your help. ^___^

The question asks that I : Find the point of intersection for each pair of lines. a) x + y= 4, x - 2y=1 b) x + 2y= 0, x - y= 3 c) 2x + y= 1, x + y= 2 d) 6x= 12 - 3y, 1/2y - x= -5 e) 1/2x - y=8, x + 1/3y= 2 f) 5 + y= 4x, x + 2= 2/3y I understand the formula of y=mx+b, m being the...

But just to make sure, induction is the proof of the nth term and (n+1)th term, right?

Mm, I asked my teacher what induction meant. I think I get the theorem now. Thanks a lot, y'all!

Induction?

The problem is, my homework requires me to explain the formulas. I understand the rest, just not why there is a 1/6 in the middle of the equation. My teacher requires that we explain why the formula is the way it is; the rest of my class is stumped too...

Erm, my friend said it was:12 + 22 + ... + n2 = 1/6n (n + 1) (2n + 1) But the problem is I have the formula I just don't know how to explain why the formula is the way it is. I just don't get the 1/6 part.

How do I simplify it? :o

A parallelepiped?! What's that? So the volume of the pyramid would be approximately: V= (h/n)(1/n)squared x A + (h/n)(2/n)squared x A +...+(h/n)(n/n)squared x A. = (Ah/n cubed)(1squared + 2squared +...+ n squared)?

Umm, you then consider each layer as a prism? So, each will be h/n units tall and the volume of the kth slab would be...er, (h/n) x (k/n)squared x A?

Ok thanks. I think I get the rest then...now for my other homework...the dreaded Pyramid Theorem! :( https://www.physicsforums.com/showthread.php?p=1301949#post1301949

Oh I see. And I suppose by area they mean the entire surface area of the cuboctahedron, right?