Homework Statement
mtan for f(x) = 5/√ 3x ... at x=1
Homework Equations
msec = y2-y1 / x2-x1
The Attempt at a Solution
The two points I got from the equation: (1, 5/√ 3) and (1+h, 5/√ 3+h)
msec = f(1+h) - f(1) / h
= (5/√ 3+h - 5/√ 3) / h ... multiply top and bottom by denominators (√ 3+h)...
EDIT:
mgh = 1/2 mv^2 ? PE = KE?
Just wondering, I calculated Potential energy and total mechanical energy as well. What could these be of use for? I feel like they should be included but I'm not sure how I could interpret them in a useful/meaningful way.
Yes, I understand that. And I also know that the total mechanical energy should be the same throughout according to the law of conservation of energy but this isn't the case due to loss of energy caused by friction and such.
I was just confused... how does this relate to the speed/velocity...
I'm doing a lab where I measure the speed of a steel marble rolling down a course with a hill and a loop. I measured distance and time in order to roughly calculate the velocity at a certain position.
My teacher wants me to compare this measured velocity with what the speed should be from...
Homework Statement
Two train whistles have frequencies of 180 Hz in air (v = 344 m/s). When one train is at rest sounding its whistle, a beat frequency of 2 Hz is heard from the moving train which is sounding its whistle as well. What is the moving train's speed if it is approaching the...
I'm confused; how could I know how many antinodes there are/what mode it's playing by the length of the clarinet and the wavelength?
Can't it only be either fundamental or third harmonic?
EDIT: Okay I just tried all the possible medium lengths to produce a wave in a media with a fixed end...
Ohhh, right...
v = fλ
λ = v/f; = 343.52m/s / 349.2Hz; = 0.98 m?
I thought there was a certain adjustment I had to do for different mediums though? In this case, a clarinet which has one open end.
Homework Statement
A clarinet behaves as an air column that is open at one end. For a particular fingering, the length of this air column is 24.6 cm. At 20°C, this fingering sounds the pitch "F" which is 349.2 Hz. During a concert, the breath of the musician raises the bore temperature to...
Okay that makes sense.
Since the time given is the time measured when it travels to the object and back, is it correct if I divide the distance I calculated by 2?
d = vav x t; = 344 m/s x (3 x 10-4 s); = 0.1032 m
0.1032 m / 2 = 0.0516 m
I thought the 3 x 10-4 s was just the chirp going to the object, and not back?
d = vav x t; = 344 m/s x (3 x 10-4 s); = 0.1032 m
Wouldn't this be the distance at which the object is at?
Okay... I kind of understand it now, but I'm still not sure how I could figure it out.
My teacher also told me something about it having 1.5 total wavelength or something?
I don't know what that means though.
Oh, I see.
(1) F1 = (345 m/s + 0 / 345 - v source) 450 Hz; truck approaching
(2) F2 = (345 m/s + 0 / 345 + v source) 450 Hz; truck going away
So there are three unknown variables here? The v source, F1, and F2...