Recent content by Hassan Raafat

Thanks a lot , this images really helped me to understand it ... I'm grateful for that my professor :smile:

If I understood u well , u mean that current will choose the shortest path to pass through (assuming all diodes are ideal) and so to have less capacitors in the path to have less impedance , right ?

I think that your last sentence is confusing me , C4 has 2 times and also C2 has 2 times so when I took the voltage on the bottom from right to left I have 4Vs - 4 Diode drops

in Voltage Tripler and Quadrupler , why don't current divide between two diodes ( D1 , D3 ) or ( D2 , D4 ) ? they are forward in the same cycle , right ? I understand that charging happens in a very little time , so two cycles already is not shown on oscilloscope but in BoyleStad is explained...

Great Video , CWatters , Really thnak you for your effort :smile:

That's great :) , big thanks NascentOxygen :smile:

Thanks a lot CWatters , I'll read it , you helped me a lot , Thanks again :)

Yes it helped a lot , Thanks berkeman :)

Thanks very much CWatters , So what you said I Can control these switches and control when to turn of the leds on , right :)

Please can you tell me how that works ?

Not for confusing you that is an idea not a real question in the picture up I have one LED working in the forward and the other is working in reverse bias where the first became off , now the question is Can I make a circuit which have three LEDs where there is one LED working in every case ...

Not exactly , I want to have three LEDs in one circuit so each time I have a specific condition , there is only one LED working

Really I don't know what they are but I wonder it because there are two-color where are green is lighted in forward and red in reverse like that , so can I make the same for three LEDs ?

Is there is a way to connect three LEDs so that there are three cases where one LED only is working in every case of the three without using micro controller ?

Thanks Very much NascentOxygen , I realized that shape of wave dosen't matter . :))