Engineering Design a clipper circuit with a specific output

AI Thread Summary
The discussion focuses on designing a clipper circuit using two diodes in opposite directions with a DC battery. The gain of 0.95 indicates that the voltage divider formed by the series and load resistors should not drop more than 5% of the input voltage. Participants discuss the calculation of resistor values to achieve the desired output voltage, which is a clipped version of the input waveform. The input waveform can be a sine wave, and its amplitude should be chosen to produce clipping at the circuit's specified levels. Ultimately, the shape of the input waveform is flexible, as long as it exceeds the clipping threshold at some points.
Hassan Raafat
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Homework Statement


upload_2016-3-25_18-5-51.png


Homework Equations



Clippers equations

The Attempt at a Solution


I knew that we will put a two diodes( with a dc battery {2.3 V} series) parallel to each other in opposite directions .. but what meant by gain is 0.95 ?
 
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Hassan Raafat said:

Homework Statement


View attachment 97926

Homework Equations



Clippers equations

The Attempt at a Solution


I knew that we will put a two diodes( with a dc battery {2.3 V} series) parallel to each other in opposite directions .. but what meant by gain is 0.95 ?
It means that the voltage divider that you form with your series resistor and the load resistor should not drop more than 5% of the input voltage when the diodes are not conducting. Can you show us your solution circuit now? :smile:
 
upload_2016-3-25_19-26-56.png
 
http://blob:https%3A//www.physicsforums.com/e4a89897-2c3c-46b3-8433-735549d386cb
 
Hassan Raafat said:
Good! Now you just have to calculate the input resistor value so that the output voltage is 0.95 * Vin...
 
Camera is not good , I can't upload complete solution but R has a value R=52.63
 
Hassan Raafat said:
but R has a value R=52.63
Can you show your equations that you used to calculate this value? It looks about right, but it would be good to see how you got it. Just type it in here... Thanks.
 
http://20160325_192231.png
 
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http://20160325_192231.png
 
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  • #10
Yeah, the pictures are not showing up. Can you just type it with text into the forum window?
 
  • #11
Vout = ( 1k / (1k+R) ) * Vin
Vout / Vin = 1k / (1k+R)
0.95 = 1000 / (1000+R)
R = 52.63 ohm
 
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  • #12
Hassan Raafat said:
Vout = ( 1k / (1k+R) ) * Vin
Vout / Vin = 1k / (1k+R)
0.95 = 1000 / (1000+R)
R = 52.63 ohm
Great! :smile:
 
  • #13
Thanks a lot , Berkeman ... You are great :)
 
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  • #14
but I still have a question what is the waveform of input voltage ?
 
  • #15
Hassan Raafat said:
but I still have a question what is the waveform of input voltage ?
Oh, that wasn't part of what you posted in Post #1. The output waveform will just be a clipped version (and 95% of) the input waveform. What kind of input waveform are you supposed to use? Sine wave? Ramp?
 
  • #16
sine wave
 
  • #17
Hassan Raafat said:
sine wave
Of what amplitude? You should be able to draw the input and output waveforms...
 
  • #18
that means that the output will be a sine wave with a peak equals (100/95) * 3 , right ?
 
  • #19
Hassan Raafat said:
that means that the output will be a sine wave with a peak equals (100/95) * 3 , right ?
Not exactly. The gain Vo/Vi = 0.95, and the Vo waveform clips at +/-3V.
 
  • #20
berkeman said:
Not exactly. The gain Vo/Vi = 0.95, and the Vo waveform clips at +/-3V.
Am I supposed to draw input in design circuits ?

And how I determine output without knowing what is the input of circuit ?
 
  • #21
Hassan Raafat said:
Am I supposed to draw input in design circuits ?

And how I determine output without knowing what is the input of circuit ?
You draw the input sine wave with some amplitude (say, +/- 5V), and then draw the output waveform which is 0.95 as big, and is clipped at +/- 3V.

One way to do it is in Excel, but you can do it by hand as well. What is the exact wording of that part of this homework problem?
 
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  • #22
Design it meant to determine value of elements in the circuit if V,I are both known
 
  • #23
Hassan Raafat said:
Design it meant to determine value of elements in the circuit if V,I are both known
You don't need to know much about input Vin. If Vin at any moment exceeds the circuit's clipping level then the output waveform will be clipped, and at those times when Vin does not reach the circuit's clipping level then there will be no clipping of the waveform.

Vin can be any waveform and the clipper will still operate. It is often convenient to illustrate the operation of a clipper using a sinewave, but you could use a triangular wave, or even random noise.

Your assignment asks you to use a sinewave input. Just choose its amplitude to be whatever is needed to produce some clipping, and sketch what the corresponding output will look like.
 
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  • #24
NascentOxygen said:
You don't need to know much about input Vin. If Vin at any moment exceeds the circuit's clipping level then the output waveform will be clipped, and at those times when Vin does not reach the circuit's clipping level then there will be no clipping of the waveform.

Vin can be any waveform and the clipper will still operate. It is often convenient to illustrate the operation of a clipper using a sinewave, but you could use a triangular wave, or even random noise.

Your assignment asks you to use a sinewave input. Just choose its amplitude to be whatever is needed to produce some clipping, and sketch what the corresponding output will look like.
Thanks Very much NascentOxygen , I realized that shape of wave dosen't matter . :))
 
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