Recent content by Hatyk

I don't think so, you can have maximum 0.3MPa in the tank, because the saturated liquid from the separator has that pressure. Continuous mixing has to happen at constant pressure and you can't increase the pressure of saturated liquid from the separator, since it's going only through reducing...

I'm not sure if I have a rough estimate. I know that the pressure in the tank has to be lower than 0.3MPa and higher than 4kPa. Pressure of 4kPa is not much realistic, so I think I can safely assume that the pressure is between 0.05MPa to 0.3MPa. But I have no further means to guess the right...

Oh, no air in the system, I thought it's just called that way even if there is no air in the system. Better translation would be feedwater tank I guess. I have no problem in determining the enthalpy of saturated liquid after the separator. Since I know the pressure in the separator I can just...

Wet steam goes into a separator at the pressure of 0.3MPAa. The separator separates this wet steam into a saturated liquid (shown as Beta in the picture) which goes into a deaerator through pressure reducing valve. This means, that the pressure in the deaerator is at most 0.3MPa. The saturated...

Homework Statement Calculate thermal efficiency of R-C cycle with saturated steam as shown in the picture. Steam has 4,5MPa when entering into HP part of the turbine (VT in the picture) and expansion on HP is finished at 0,3MPa. Moisture is then removed in the separator and steam is overheated...

Homework Statement I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc. Homework Equations dQ=ρ2πr^2 I would use this equation if the charge density was uniform The Attempt at a Solution My first idea...