Recent content by henryli78

Thank you! I solved it :)

Do you mean alpha = a/r?

Ok thank you. I guess my mistake was just in bad algebra :P

Thank you! I solved it. I wrote out: Net Torque = I*alpha = I*a/R2 = F*R1 - T*R2 T = ma, thus I*a/R2 = F*R1 - m*a*R2 I*a/R2 + m*a*R2 = F*R1 a(I/R2+mR2) = F*R1 a(I + mR2^2) = F*R1*R2 a = F*R1*R2/(I+mR2^2) Thank you very much for the help :)

Ok I get: For the mass: m_1*g - T_1 = m_1*a For the disk: mg + T_1 = T_2 I*alpha = T_1*r Is this ok so far?

Homework Statement Answer: C Note: Sorry admins for the picture, needed to include the diagram though. Homework Equations ∑\tau = I\alpha ∑F = ma a = \alphar The Attempt at a Solution The torques must be balanced (is this reasoning already wrong?), thus, F*R1 = F_T*R2 F_T =...

Homework Statement A 0.70-kg disk with a rotational inertia given by MR^2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling. A string is wrapped around the disk and a 2.0-kg mass hangs from the free end. If the string does not slip, then as the mass falls and the...

Homework Statement A 8.0-cm radius disk with a rotational inertia of 0.12 kg*m^2 is free to rotate on a horizontal axis. A string is fastened to the surface of the disk and a 10-kg mass hangs from the other end. The mass is raised by a using a crank to apply a 9.0-N*m torque to the disk. The...

Ok thank you very much! I had a hard time really understanding my error but now I get it. Thanks!

Ahh I forgot to search first. But is it possible if someone could point out where I have a flaw in my logic? I understand the solution's concept but I get why my answer is different.

Homework Statement A proton is a distance d/2 directly above the center of a square of side d. What is the magnitude of the electric flux through the square?Homework Equations 1. Electric flux, \Phi_{net} = \oint \vec{E}\cdot d\vec{A} 2. \Phi_{net} = \frac{q_{enc}}{\epsilon_{0}} 3. \vec{E} =...