Recent content by hiddenlife5009

Ok, thanks for the very descriptive reply, but could you explain a couple things. First of all, what is it meant by the term 'dyne-cm'? Also, when you talk about for example, '-(49.5)mg', that's force right? You also say 36.6cm from the left end, do you mean 38.6? Edit: Sorry, but I have...

Homework Statement A metre stick is found to balance at the 49.5cm mark when placed on a fulcrum. When a 47.7 gram mass is attached at the 1.5cm mark, the fulcrum must be moved to the 38.6cm mark for balance. What is the mass (in grams) of the metre stick. Homework Equations Torque =...

I have read your post over and over, and from what I understand, you mean the velocity I calculated was off by a factor of 10. I understand the whole method of finding the revolution per seconds now, but can't understand how I would go about obtaining a value for time and number of turns...

Sorry, I don't follow. I understand my fault with trying to find out the velocity, but I'm not sure where I go after finding the circumference, which is 98.65cm.

Homework Statement A sample of blood is placed in a centrifuge of radius 15.7 cm. The mass of a red corpuscle is 3.09×10-16 kg, and the magnitude of the force required to make it settle out of the plasma is 4.01×10-11 N. At how many revolutions per second should the centrifuge be operated...

I'm quite sure its not missing, I think its trying to say "to a full speed of 31.3 m/s within seconds", meaning it can get to the max speed within a general time frame of a few seconds (insignificant). I guess its just trying to tell you its max speed. EDIT: Hage567 - Thanks for that, by...

Homework Statement Part A A cheetah, the fastest of all land animals over a short distance, can accelerate from zero to 18.0 m/s in three strides and to a full speed of 31.3 m/s in seconds. Assuming the first three strides are each 4.2 m long and that acceleration is constant until the...

So therefore, v = (2x9.8x90.49)^0.5 = 42.11 m/s I'm fairly certain that is the answer. Thankyou very much for being so patient with me and helping me out, its my first time doing physics. On a side note, there is another I need a tiny bit of help on. Got the first part of this...

Ok, so using that equation, I have gotten distance = 8.49m Is that the maximum height the stone reaches? If so, where do I go from here to obtain the speed of the stone just before it hits the ground?

Not really. For starters, u = height?, and could you please refer to my previous post for the second bit I don't understand.

Ah, height is part of the question, but I guess you meant 82, you wrote down 85. And what do you mean by add s (seconds I presume) to 82 (height)?

Sorry, but where are you getting 85 from?

Homework Statement In part (a) of this question suppose a stone is thrown verically upward with a speed of 12.9 m/s from the edge of a cliff and that h = 82 m. At what speed (in m/s) does the stone hit the ground? Homework Equations T = v/g Free fall equation V = (V^2 - 2gvt ...

Thanks for the help, I have worked it out now.

Homework Statement A cheetah, the fastest of all land animals over a short distance, can accelerate from zero to 18.0 m/s in three strides and to a full speed of 31.3 m/s in seconds. Assuming the first three strides are each 4.1 m long and that acceleration is constant until the cheetah...