Recent content by Iamaskier721

http://wps.prenhall.com/wps/media/objects/224/229574/ch5/f8-3.gif That's the image they give me to solve the problem. Can yo uhelp with the steps I should use to solve this problem?

Homework Statement A ball starting at h= 9.9 meters slides down a smooth surface where it encounters a rough surface and is brought to rest at B a distance 26.2 meters away. If the ball has a mass of 0.97 kg, to the nearest joule, what is the work done by friction? Any help to start this...

Homework Statement The green block is falling at a speed of 20 m/s and is 7 meters above the spring. The spring constant is 4155 N/m, to the nearest tenth of a cm how far is the spring compressed? The answer to that part is 10.6cm The next part is what I'm having difficulty with... In...

So it is being displaced 1.83 m veritcally. I Figured this out by the law of sines and a simple right triangle. What is the next step to solving this?

Homework Statement A man pulls a 10 kg box across a smooth floor with a force of 87 Newtons at an angle of 24 degrees and for a distance of 76 meters. How much work, to the nearest joule, does he do? If the floor in the previous question is angled upward at 10.6 degrees and the man pulls...

I'm sorry to write this but there is a second part I need help with =/ In the previous problem to the nearest hundredth of a meter to what height will the block rise after it hits and leaves the spring? Would I just figure out the force that can be exerted by the spring on the object from...

So the equation is 856.4= 1/2 x 3860 x X^2? I get the answer 66.6 cm or.6661 m Is this correct?!

I used the formula you gave me which was v^2= 22m/s^2 + 2(9.8)(19) which equals 29.26 (whoops!) is that correct? Then I put it into k=1/2 x m x v^2 ? And when that answer is found put it into the simple work equation of w=f x m. So that 856.4= f x 2. Therefore the force is 428.2 n/m.

For the velocity I achieve 24.8 m/s just before it hits the block and then i found the energy of 1211.84. If i use that in the Work= Force x Mass [1211.84= F x 2kg] I get the force correct? If that is right then the force of the block is 605.52. So then I plug that into the equation x= spring...

Well i Found the total mechanical Energy of the block which is 836 j. And the velocity just before it hits the spring is 28.91 m/s. So therefore it hits the spring with a force of 57.82 n. What would be the next step?

Homework Statement The green block is falling at a speed of 22 m/s and is 19 meters above the spring. The spring constant is 3860 N/m, to the nearest tenth of a cm how far is the spring compressed? The Block Weighs 2 Kg I have no idea on how to solve this...

Homework Statement I. A 2kg block is falling at a speed of 20 m/s and is 18 meters above the spring. The spring constant is 4134 N/m, to the nearest tenth of a cm how far is the spring compressed? II. In the previous problem to the nearest hundredth of a meter to what height will the block...

Ah I finally got it! Thankyou all! The 3.08 seconds was just relevant to the next question which was find the power in watts and that is just work divided by time. Thanks again!

Well the formula for work is obviously Force times Displacement and the formula for energy is 1/2 mass times the velocity squared. Do I just find the difference in their enery?

You are traveling in your 2000 kg car at 9.2 m/s and wish to accelerate to 17.5 m/s in 3.08 seconds, how much work, to the nearest joule, is required? Okay so i don't even know hwo t ostart this problem. I know I need to find the initial amount of work being done by the car and then...