Work Done by Friction on 0.97 kg Ball Starting at h=9.9m

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The discussion revolves around calculating the work done by friction on a 0.97 kg ball that slides down from a height of 9.9 meters and comes to rest after traveling 26.2 meters on a rough surface. Participants emphasize the conservation of energy, noting that the potential energy at the height is converted to kinetic energy, which is then dissipated by friction. The importance of understanding the relationship between potential energy, mass, height, and work done against friction is highlighted. Some users suggest that the original poster should derive relevant equations rather than receiving them directly to enhance learning. The conversation ultimately focuses on guiding the original poster to solve the problem independently.
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Homework Statement


A ball starting at h= 9.9 meters slides down a smooth surface where it encounters a rough surface and is brought to rest at B a distance 26.2 meters away. If the ball has a mass of 0.97 kg, to the nearest joule, what is the work done by friction?

Any help to start this problem off?
 
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Iamaskier721 said:

Homework Statement


A ball starting at h= 9.9 meters slides down a smooth surface where it encounters a rough surface and is brought to rest at B a distance 26.2 meters away.

You have not given the complete geometry of the problem. Is the rough surface horizontal?

Anyway, the ball at the top had some property due to its height and that quantity is always conserved, and here it is dissipated totally by friction. That should be enough to answer the question.

As per your request, I'm just trying to start you off.
 
I wouldn't like to give you all the mathematical steps, but you should be able to solve this from whatever hint I am giving you.

When a mass is raised by a height h from some point, it gains some potential energy. When you let it fall back to its original level, this potential energy is converted into kinetic energy due to motion. Here, the ball stops because of friction. So where has all the kinetic energy gone? Has it got anything to do with the frictional force which opposes motion? Try to remember what is meant by "work done" .
 
You might have seen the following two equations in class, they might be a good starting point.

<< equations deleted by berkeman >>

For the original poster (OP) -- the equations that Banaticus wants you to think about relate

-1- the relationship between Potential Energy, the mass of an object, and the height to which it is lifted...

-2- the relationship between work done on an object, and the distance through which a force is applied...

Can you write out the two equations that Banaticus is referring to?

 
Last edited by a moderator:
Banaticus said:
You might have seen the following two equations in class, they might be a good starting point.

<< equations deleted by berkeman >>

For the original poster (OP) -- the equations that Banaticus wants you to think about relate

-1- the relationship between Potential Energy, the mass of an object, and the height to which it is lifted...

-2- the relationship between work done on an object, and the distance through which a force is applied...

Can you write out the two equations that Banaticus is referring to?

Sorry to have to edit your post, Banaticus. Giving the equations outright was a bit too much help. It takes a bit of practice to figure out how to help the OP to do the work themselves -- we definitely appreciate the help here!
 

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