Recent content by IAmSparticus

1.A suitcase (mass m = 16 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50 m by 0.14 m. The elevator is moving upward, the magnitude of its acceleration being 1.40 m/s2. What pressure (in excess of atmospheric pressure) is applied to...

So if I leave it in the symbol format I get that (.69kg)(9.8m/s/s)=kx and m(9.8m/s/s)=k(5x). Now what?

1. A 0.69 kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one, and the amount that the spring stretches from its unstrained length increases by a factor of 5. What is the mass of the second block? 2. Force= spring...

Is it 16.165 cm (.16165 m)?

1. You are installing a new spark plug in your car, and the manual specifies that it be tightened to a torque that has a magnitude of 26 N·m. Using the data in the drawing, determine the magnitude F of the force that you must exert on the wrench. 2. Torque= Force * Lever arm length...

1. The Earth spins on its axis once a day and orbits the sun once a year (365.24 days). Take the positive direction for the angular displacement to be the direction of the Earth's motion. Express your answers in radians/second. 2. Wavg = Delta Theta / Delta Time Delta Theta is in radians...

1. The Earth spins on its axis once a day and orbits the sun once a year (365.24 days). Take the positive direction for the angular displacement to be the direction of the Earth's motion. Express your answers in radians/second. 2. Wavg = Delta Theta / Delta Time Delta Theta is in radians...

1. A car (mass = 1060 kg) is traveling at 43 m/s when it collides head-on with a sport utility vehicle (mass = 2550 kg) traveling in the opposite direction. In the collision, the two vehicles come to a halt. At what speed was the sport utility vehicle traveling? 2. COLM states: m1Vf1 +...

That is much easier... thank you so much!

Thank you very much, I'm not too good at this stuff...

Would it be that the final kinetic energy is 6.5% of the original kinetic energy, so 93.5% of the kinetic energy was lost? Or did I do it completely wrong?

Ok so if I plug in the values of m1 and m2, I get an equation of 2.6kg Vf = .17 Vi1. Is this correct? Now the next step I am a little confused on. If I divide both sides by 2.6 to find the ratio of Vf to Vi1, I get that Vf=.065Vi1. Is this correct or should I have done the opposite (find Vi1...

So I would just solve the equation mVf -mVi? Which would be (.28kg)(3.57 m/s) - (.28kg)(-4.85 m/s) = 2.3576 kg*m/s?

How would I manipulate the variables to obtain this ratio?

Ok, so I got a final (post-collision) velocity of 3.57 m/s. Does this seem right? What would I do next? I notice we still don't have a number for the time interval, how would I go about figuring that out?