What Went Wrong with Calculating Impulse in Impulse-Momentum Theory?

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Homework Help Overview

The discussion revolves around calculating impulse using the Impulse-Momentum Theory in the context of a ball dropped from a height and rebounding after hitting the ground. Participants explore the implications of initial and final velocities in the calculation of impulse.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct identification of initial and final velocities, questioning the assumptions made about these values. There is exploration of how to incorporate the rebound height into the calculations and whether the time interval is necessary for solving the problem.

Discussion Status

Some participants have provided guidance on the interpretation of initial and final velocities, while others are verifying their calculations and seeking confirmation on their results. The conversation reflects a mix of attempts to clarify concepts and resolve misunderstandings without reaching a definitive conclusion.

Contextual Notes

There is a noted lack of information regarding the time interval for the collision, which some participants mention is not necessary for calculating impulse. The original poster expresses uncertainty about their understanding of the concepts involved.

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1. A 0.280 kg ball is dropped from rest at a point 1.20 m above the floor. The ball rebounds straight upward to a height of 0.650 m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor?



2. Impluse-Momentum Theory: Sum of Forces * time inerval = m Vf - mVo
Momentum = p= mV


3. I found the final velocity of the ball when it has been dropped (4.85 m/s, I found this out using the equation y= (Vf^2 -Vo^2)/2a ), but when I tried to plug it into the IMT, I got an answer of 1.36 kg*m/s, which is apparently wrong. Where did I go wrong? I assumed the initial velocity to be zero since it was dropped from rest. Is there something I was supposed to do with the rebounded part?
 
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"Initial velocity" for the equation is not zero; it is the velocity of the ball upon hitting the ground. In this case we are interested in the change in momentum of the ball due to the net force acting upwards on it when it hits the ground, so initial momentum = instantaneous momentum of the ball as it hits the ground, and final momentum = instantaneous momentum of the ball as it rebounds from the ground.
 
IAmSparticus said:
3. I found the final velocity of the ball when it has been dropped (4.85 m/s, I found this out using the equation y= (Vf^2 -Vo^2)/2a ), but when I tried to plug it into the IMT, I got an answer of 1.36 kg*m/s, which is apparently wrong. Where did I go wrong? I assumed the initial velocity to be zero since it was dropped from rest.
In this context, initial and final velocity mean the velocities immediately before and immediately after the collision. Vo = 4.85 m/s (not zero!) downward.
Is there something I was supposed to do with the rebounded part?
Yes. Use the given data to find the final (post-collision) velocity. (Just like you found the initial (pre-collision) velocity.)
 
Ok, so I got a final (post-collision) velocity of 3.57 m/s. Does this seem right? What would I do next? I notice we still don't have a number for the time interval, how would I go about figuring that out?
 
IAmSparticus said:
Ok, so I got a final (post-collision) velocity of 3.57 m/s. Does this seem right? What would I do next? I notice we still don't have a number for the time interval, how would I go about figuring that out?
The question asked for the impulse, not average force, so you don't need the time interval. (not enough information is provided to compute it in any case)
 
So I would just solve the equation mVf -mVi?

Which would be (.28kg)(3.57 m/s) - (.28kg)(-4.85 m/s) = 2.3576 kg*m/s?
 
Looks correct to me :)
 
Thank you very much, I'm not too good at this stuff...
 

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