hihihi. Yes, he you're right! However, I thought, if they don't give us the answer,they will at least give us the value of either n or m, or the ratio b/t these two variables in order to solve the equation. Thanks for your comment, Mark. You have a nice day!
[SIZE="3"]Can anyone help me with this problem?
Homework Statement
Supposed A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the values:
a. 2/3; 1/3
b. 2; 3
c. 4/5; 3/5
d. 1/5; 3/5
Homework Equations
N/A...
Homework Statement
Consider the following gas phase reaction:
http://scholar.uh.edu/webct/RelativeResourceManager/Template/Imported_Resources/20053H_CHEM1331_08946_QIZ_200511041405291131475017966%20folder/QIZ_6442871_M/my_files/test_images/f5g1q49g1.gif
400. mL of NO at STP is reacted with...
Hi, I found the right answer: N2O4.
Here is my works:
1. I found the mass of each gas in the compound using the given % by mass.
mass of N= .304*5.25= 1.596g N
mass of O= 5.25 - 1.596= 3.654g O
2. Mass-Mole conversion:
1.596g N* 1mol of N/ 14.01g of N = 0.1139 mol N
3.654g O* 1mol of O/ 16g of...
Homework Statement
A gaseous compound is 30.4% nitrogen and 69.6% oxygen by mass. A 5.25 g sample of the gas occupies a volume of 1.00 L and and exerts a pressure of 1.26 atm at -4.0C. Which of the following is its molecular formula?
Variables:
30.4% Nitrogen
69.6% Oxygen
M(sample)= 5.25g
P=...
So, I have the result:
Ax'= 8cos37x'-hat= (6.4x'-hat)
Ay'= -8sin37y'-hat = -4.8y'-hat
Bx'= 6cos37x'-hat= 4.8x'-hat
By'= 6sin37y'-hat = 3.6y'-hat
Is it right?
I found the answer for the first part of the problem to be 10 units. But I have no clue how to deal with the second part :) Please give some hints how to solve this following prob.
Homework Statement
Two vector A and B, are drawn on an x-y coordinate system as shown. Vector A has a...
Really!? Thanks.
By the way. I think I post this in the wrong section. If you can, please move this post to the proper section. I will read the regulations and follow them the next times.
This is how i worked it out:
CaCl2 + 2H2O => Ca(OH)2 + 2HCl
Mol of Cl:
341mL * (1L/1000mL) * 0.23 mol/L= 0.078 mol of Cl
Vol. of CaCl2:
0.078 mol Cl * (1mol CaCl2/2mol Cl) * (1L/0.98 mol CaCl2) * (1000mL/1L) = 40.0 mL CaCl2
I TRIED HARD ON THIS... IS THIS THE RIGHT ANNSWER!
If I understand the problem correctly, I should find how many mol of chloride ions is produced by one mol of calcium chloride first. DO you think that is right?