Recent content by idk11

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    Ultracapacitors - How long until the potential difference drops to 6V

    Okay. So I got the correct answer by finding the new Q and plugging it into that equation you gave me for the first part of the question. However, I still do not know where you derived that equation from. My class is strictly algebra-based and we have not even mentioned differentials yet. ΔQ/I...
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    Ultracapacitors - How long until the potential difference drops to 6V

    Yes, it has changed. I realize that, but what equation am I missing that relates all of these elements to time? In my notes from class, I recorded that, when something is discharging... V(t)=V(0)e(-t/t-constant) Would I find a new initial voltage through Q=VC and plug it into that equation I...
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    Ultracapacitors - How long until the potential difference drops to 6V

    That's what I meant to say. Once I have the two equivalent capacitances, what equations do I plug them into?
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    Ultracapacitors - How long until the potential difference drops to 6V

    If two of these capacitors are placed in a series, how long (in days) would it take? In parallel? I can calculate the two equivalent resistances for this question, but are they even really needed?
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    Ultracapacitors - How long until the potential difference drops to 6V

    Where exactly was I going wrong above then?
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    Ultracapacitors - How long until the potential difference drops to 6V

    Homework Statement Compact "ultracapacitors" are with capacitance values up to several thousand farads are now commercially available. One application for ultracapacitors is in providing power for electrical circuits when other sources (such as a battery) are turned off. Assume a 1200-F...
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    Solve Electric Field Homework: Find x Coordinate for E=0

    Homework Statement A 1.8e-6 C charge is at the origin, while a -7.71e-6 C charge is 10cm to the right of it. Locate the x coordinate such that E=0. Note: q1 is at the origin O. Answer in units cm. Homework Equations Etot=E1+E2 Etot=(-k*q1/x^2)+(k*q2/(0.1+x)^2)...
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