Recent content by ilovejava

Homework Statement In a colliding beam apparatus, two beams of protons are aimed at each other. The first proton moves with a speed of 0.82c to the right; the second moves with a speed of 0.86c to the left. Both speeds are measured relative to the laboratory frame of reference. What is the...

Yes, my fault should've included units. Sorry for the confusion.

E = E0 + KE Therefore, E = E0 + KE becomes E = 938MeV + 530MeV E = 1468MeV Now, let's use the equation E = E0 / √1-(v2/c2) E√1-(v2/c2) = E0 √1-(v2/c2) = E0 / E 1 - (v2/c2) = (E0/E)2 v2/c2 = 1 - (E0/E)2 Solve for V and you will get 2.3E8

As a follow up question. If I want to find the mass of this proton how would I go about doing that. There is m = m0 / √1-(v2/c2). The speed of the proton turned out to be 2.306E8 C, but if I plugged that into the formula I would get a negative answer in the denominator. So, how can I find the...

Haha. You guessed correctly, he wants us to use relativistic mass.

This is what I have been using and and I get 2.306E8 C as my final answer if I used joules. Next, keeping MeV is neat because it you get to work with smaller numbers, and using the numbers provided in the question I would get 2.307E8 C as my final answer. As a follow up if I wanted to find the...

I apologize, E/E0 yields 1.56 and it was E0/E that gives 0.639

I apologize E0/E = 0.63957. It's funny because our professor told us to convert to joules first, so it makes it easier working with the units. If I did do the problem in MeV the approach would be the same right?

The rest energy of the proton (E0) is 1.503E-10 and the total energy of the proton (E = KE + E0) is 2.35E-10, so I don't know what you mean when the proton can't have less energy than its rest energy.

I found E0 = 1.503E-10 and E/E0 = 0.63957

Homework Statement In a proton linear accelerator, protons are accelerated to have a kinetic energy of 530 MeV. What is the speed of these protons? (The rest mass of a proton is 1.67 × 10-27 kg.) Homework Equations E0=m0c^2 E=E0/√1-(v^2)/(c^2) E = KE + E0 The Attempt at a Solution Recognize...

I drew one out and it appears that the image forms behind the convex mirror. So this would be a virtual object does that mean I should have made 20.8 negative?

Homework Statement A concave mirror (f1 = 13.6 cm) and a convex mirror (f2 = −7.00 cm) are facing each other and are separated by a distance of 35.8 cm. An object is placed between the mirrors and is 17.9 cm from each mirror. Consider the light from the object that reflects first from the...

Homework Statement A farsighted man uses eyeglasses with a refractive power of 2.05 diopters. Wearing the glasses 0.020 m from his eyes, he is able to read books held no closer than 0.265 m from his eyes. He would like a prescription for contact lenses to serve the same purpose. What is the...

Homework Statement Three polarizing disks whose planes are parallel and centered on common axis. The directions of their transmission axes relative to the vertical are respectively: θ1 = 33° clockwise, θ2 = 21° counter-clockwise, and θ3 = 25° clockwise. A beam of light polarized along the...