you are making your life complicated... this question is doable according to your prof. You are thinking too hard.. it's a really simple question. you are messing with too many variables. just think about what the doubling is affecting.. sorry I cannot help.. I have class to get to.
just wondering
:confused: does the Br attach to the methyl group making it CH2Br-cyclopenane?
or does it attach to the carbon that is attached the the methyl group making it 1-bromo-1-methylcyclopentane?
my work
Here is my work... I'm not 100% sure.. This questions is hard...
Mass = 2.00 kg
F= 20.0 N
x = 0.200m
(a) finding K
F= 0.5kx^2 if that is the right formula
20.0 N = 0.5k(0.2)^2
K= 1000 N/m
(b) Since w is also frequency but is in s^-1
w= (k/m)^1/2
w= (1000/2.00)^1/2
w=...
Can someone please help me with this question?:confused:
A 2.00-kg object is attached to a spring and placed on a horizontal, smooth surface. A horizontal force of 20.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis)...
:confused: Can someone please help me?
A horizontal string can transmit a maximum power (without breaking) if a wave with amplitude A and angular frequency is traveling along it. To increase this maximum power, a student folds the string and uses this "double string" as a medium. Determine...
Ok.. Final Answer...
I changed my mind.. to have the smallest heat of combustion, the compound must be the least stable..
and if we had 5 choices:
A) Cyclopentane
B) Methylcyclopropane
C)1,1-Dimethylcyclopropane
D) cis-1,2-dimethylcyclopropane
E) trans-1,2-Dimethylcyclopropane
C)...
Well...
cis-1,2-dimethylcyclopropane has a larger negative heat of combustion than trans-1,2-Dimethylcyclopropane.
The c-c bonds in cyclopropane are bent... which makes for weaker bonds.. so now its E