Formation of Bromocyclopentane from Br2 and 1-Methylcyclopentane

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When Br2 is added to 1-methylcyclopentane, bromination occurs primarily at the carbon with the methyl substituent due to its higher reactivity. The expected product is bromocyclopentane, specifically 1-bromo-1-methylcyclopentane, rather than the proposed structures. The reaction mechanism involves radical formation, which is influenced by the conditions under which the reaction is conducted, such as mixing versus burning. Understanding the reactive groups and the mechanism is crucial for predicting the correct product. Overall, the formation of bromocyclopentane from Br2 and 1-methylcyclopentane highlights the importance of reaction conditions and substitution patterns.
ilovephysicssomuch
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what is the product formed when Br2 is added to 1-methylcyclopentane?
 
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im thinking CH3CH2CH2CH2CBr3.. is that correct?
another answer i was thinking of is..
CH3Ch2CHBrCH2CBr3
 
First you need to find out what the reactive groups are, then what the reaction mechanism is. Can you make a guess?
 
ilovephysicssomuch said:
what is the product formed when Br2 is added to 1-methylcyclopentane?
Mixing it or burning it? Yes, it makes a huge difference.

Also, try not to express your cyclic answers as straight chains. I know it's hard to express cyclic answers, but try to put into words what you think is happening.

Whatever happens, it will probably happen to the carbon with the methyl group on it since that's the most substituted.
 
be sure to state the full conditions of the reaction, especially all of the reagents.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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