Recent content by im2fastfouru
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Understanding Inverse Images and Continuity in Real Analysis
1. a) Show that (f^-1 S)compliment = f^-1(S compliment) for any set S of reals. Then use part a) to show The function f is continuous iff f^-1(S) is closed for every closed set S. 2. inverse image = f^-1(S) = {x: f(x) \in S} f is continuous iff for every open set U \in the reals...- im2fastfouru
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- Continuity Image Inverse
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Graduate Is f continuous if f^-1(S) is closed for all closed sets S?
Any help on this problem would be appreciated a) Show that (f^-1 S)compliment is equal to f^-1(S compliment) for any set S of reals. Then use part a) to show The function f is continuous iff f^-1(S) is closed for every closed set S.- im2fastfouru
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- Continuity Image Inverse
- Replies: 2
- Forum: Calculus
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Undergrad Product of two continous functions
There is a proof in my book that asks us to prove that the product of two continuous functions is continuous. If anyone could help please reply back, thanks!- im2fastfouru
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- Functions Product
- Replies: 8
- Forum: Calculus
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Undergrad Proving Power Set Inclusion: A Simple Proof for A⊆B and P(A)⊆P(B)
x is just an arbitrary element. And if A \subseteq B then prove P(A) \subseteq P(B). This need to be proved formally as well for my assignment!- im2fastfouru
- Post #7
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Power Set Inclusion: A Simple Proof for A⊆B and P(A)⊆P(B)
i'm more inclined to start with x \in P(a), can i start the proof this way?- im2fastfouru
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Proving Power Set Inclusion: A Simple Proof for A⊆B and P(A)⊆P(B)
This seems like a simple proof but I'm not familiar with power set proofs If A\subseteqB then P(A) \subseteq P(B)- im2fastfouru
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- Power Power set Proof Set
- Replies: 7
- Forum: Set Theory, Logic, Probability, Statistics